Question

Every integer is a natural number, if true then enter \[1\], and if false then enter $0$.

Answer 1

Hint:
This question is based on the concept of natural numbers and integers and if we know about them then we can easily answer them. The natural numbers are those numbers that we use for counting and an integer is a whole number. Whenever communicated as a portion, it can generally be diminished without yielding another part.

Complete step by step solution:
As we know that the natural numbers are those numbers which started as $1,2,3......$and so on. And the integers are those numbers which started as $.... - 4, - 3, - 2, - 1,.......1, 2, 3, 4.....$and so on. So from this, we can say that every integer cannot be a natural number. So the statement we have got it wrong.

Therefore, the statement is false, that is we can enter $0$.

Additional information:
A Natural number is a whole number that we use for counting. They have an order that we learn when we are very young: one, two, three, and four, and so on. They go on indefinitely: there is always a next one which is different from any that has gone before, and we never get back to the start.
Having also defined addition and multiplication we can represent larger Natural numbers using positional notation. We are generally acquainted with decimal where each position speaks to a factor of ten, yet we can utilize any base.
Integer Number is a number that includes $0$ and negative number, with no fractional portion.
Which means Integer is not in $p/q$ form. So every number which is not in $p/q$ the form be it a negative, a positive, or $0$ except imaginary numbers is an Integer. The number line Consists of a negative number, neutral number, and Positive number, so it has everything in it.

Note:
From the above discussion we can conclude that the integer cannot be in the form of $p/q$ and also $0$ is an imaginary integer number. So to answer this type of question the only thing needed is the concept of these terms.