Answer

Verified

420.9k+ views

**Hint:**Here, we will use the basic identities of the trigonometric functions to find out the value of the given equation. So we will rewrite the terms given in the equation as a sum of degrees by applying the properties of the trigonometric function. Then we will use the periodicity of the trigonometric function and simplify the equation. We will then substitute the values of the function to get the value of the equation.

**Complete step-by-step answer:**Let \[\cos 225^\circ - \sin 225^\circ + \tan 495^\circ - \cot 495^\circ = T\].

First, we will simplify the given equation by writing the trigonometry functions of the equation in the form of the quadrants.

We can write \[\cos 225^\circ = \cos \left( {180^\circ + 45^\circ } \right)\], \[\sin 225^\circ = \sin \left( {180^\circ + 45^\circ } \right)\], \[\tan 495^\circ = \tan \left( {5 \times 90^\circ + 45^\circ } \right)\] and \[\cot 495^\circ = \cot \left( {5 \times 90^\circ + 45^\circ } \right)\]. Therefore, we get

\[ \Rightarrow T = \cos \left( {180^\circ + 45^\circ } \right) - \sin \left( {180^\circ + 45^\circ } \right) + \tan \left( {5 \times 90^\circ + 45^\circ } \right) - \cot \left( {5 \times 90^\circ + 45^\circ } \right)\]

Also we know that \[\cos \left( {180^\circ + \theta } \right) = - \cos \theta \] and \[\sin \left( {180^\circ + \theta } \right) = - \sin \theta \] as in the third quadrant both the sin and the cos function is negative.

\[\tan \left( {5 \times 90^\circ + \theta } \right) = - \cot \theta \] and \[\cot \left( {5 \times 90^\circ + \theta } \right) = - \tan \theta \] as in the second quadrant both the tan and the cot function is negative. Therefore the equation becomes

\[ \Rightarrow T = - \cos \left( {45^\circ } \right) - \left( { - \sin \left( {45^\circ } \right)} \right) - \cot \left( {45^\circ } \right) - \left( { - \tan \left( {45^\circ } \right)} \right)\]

\[ \Rightarrow T = - \cos \left( {45^\circ } \right) + \sin \left( {45^\circ } \right) - \cot \left( {45^\circ } \right) + \tan \left( {45^\circ } \right)\]

Now we will put the values of the trigonometric functions and solve this to get the value of the expression. Therefore, we get

\[ \Rightarrow T = - \dfrac{1}{{\sqrt 2 }} + \dfrac{1}{{\sqrt 2 }} - 1 + 1\]

\[ \Rightarrow T = - \dfrac{1}{{\sqrt 2 }} + \dfrac{1}{{\sqrt 2 }} - 1 + 1 = 0\]

\[ \Rightarrow \cos 225^\circ - \sin 225^\circ + \tan 495^\circ - \cot 495^\circ = 0\]

**Hence, the value of the equation \[\cos 225^\circ - \sin 225^\circ + \tan 495^\circ - \cot 495^\circ \] is 0.**

**Note:**We should know the different properties of the trigonometric function and also in which quadrant which function is positive or negative as in the first quadrant all the functions i.e. sin, cos, tan, cot, sec, cosec is positive. In the second quadrant, only the sin and cosec function are positive and all the other functions are negative. In the third quadrant, only tan and cot function is positive and in the fourth quadrant, only cos and sec function is positive.

Recently Updated Pages

How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE

Mark and label the given geoinformation on the outline class 11 social science CBSE

When people say No pun intended what does that mea class 8 english CBSE

Name the states which share their boundary with Indias class 9 social science CBSE

Give an account of the Northern Plains of India class 9 social science CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

Trending doubts

Difference Between Plant Cell and Animal Cell

Which are the Top 10 Largest Countries of the World?

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

How do you graph the function fx 4x class 9 maths CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths