Question

Evaluate $$6-8-(-6)÷2$$.

Answer 1

Hint: Here we have a simple algebraic expression, we need to simplify it by applying the given operations. That is addition, subtraction, division and multiplication. To solve this we follow the BODMAS rule. This rule states that when given an equation or expression, we should first calculate the brackets, then any order, then division, then multiplication, then addition and then subtraction.

Complete step by step solution:
Given,
$$6-8-(-6)÷2$$
By BODMAS rule we simplify the brackets,
 $$\Rightarrow 6-8+6÷2$$
Now we need to simplify the division part,
 $$\Rightarrow 6-8+{\displaystyle \frac{6}{2}}$$
$$\Rightarrow 6-8+3$$
Now adding we have,
$$\Rightarrow 9-8$$
Now subtracting
$$\Rightarrow 1$$
Thus the value of the algebraic expression is $$6-8-(-6)÷2=1$$.

Additional information:
Suppose they are given to simplify this $$\left(6-8-(-6)\right)÷2$$.
Then we need to simplify the terms inside the brackets and then we apply the division.
$$\left(6-8+6\right)÷2$$
$$\left(12-8\right)÷2$$
$$\Rightarrow 4÷2$$
$$\Rightarrow 2$$

Note:
We know that the product of two negative numbers results in a positive number. The product of a positive (negative) number and a negative (positive) number results in a negative number only. Sometimes BODMAS is also called as BIDMAS. Where ‘I’ is index and rest is the same. If we do the calculation with applying this rule we will get a wrong answer.