
Equivalent mass of ferrous oxalate in the following reaction is: .
A)
B)
C)
D)
Answer
446.7k+ views
2 likes
Hint: The equivalent mass of an oxidant or reductant is that mass which either supplies or consumes one mole of electrons in a redox reaction.
In a reaction, we can calculate the equivalent mass by using the following relation
For this purpose, we need to first calculate the n factor. n factor gives the number of electrons lost or gained by an oxidant or reductant.
Complete step-by-step solution:
The reaction is the oxidation half reaction in which ferrous oxalate is oxidized to ferric ions and carbon dioxide ions. Increase in the oxidation number is oxidation and decrease in the oxidation number is reduction.
The oxidation number of iron in ferrous oxalate is +2. In ferric ions, the oxidation number of iron is +3. Thus, during the reaction, the oxidation number of iron increases from +2 to +3. Thus, iron is oxidized during the reaction.
Ferrous ion loses a proton to form ferric ion.
Similarly, an oxalate ion loses two electrons to form two molecules of carbon dioxide.
During this reaction, oxalate ion is oxidized to carbon dioxide. Loss of electrons is oxidation and gain of electrons is reduction.
One molecule of ferrous oxalate loses three electrons to form one ferric ion and two carbon dioxide molecules.
Here, the value of n factor is 3.
Equivalent mass of ferrous oxalate in the reaction is
Hence the correct answer is option ‘C’.
Note: In a redox reaction, n factor is the number of electrons that participate in the half reaction. We can also calculate the n factor from the change in the oxidation number.
In a reaction, we can calculate the equivalent mass by using the following relation
For this purpose, we need to first calculate the n factor. n factor gives the number of electrons lost or gained by an oxidant or reductant.
Complete step-by-step solution:
The reaction
The oxidation number of iron in ferrous oxalate
Ferrous ion loses a proton to form ferric ion.
Similarly, an oxalate ion loses two electrons to form two molecules of carbon dioxide.
During this reaction, oxalate ion is oxidized to carbon dioxide. Loss of electrons is oxidation and gain of electrons is reduction.
One molecule of ferrous oxalate
Here, the value of n factor is 3.
Equivalent mass of ferrous oxalate
Hence the correct answer is option ‘C’.
Note: In a redox reaction, n factor is the number of electrons that participate in the half reaction. We can also calculate the n factor from the change in the oxidation number.
Latest Vedantu courses for you
Grade 9 | CBSE | SCHOOL | English
Vedantu 9 CBSE Pro Course - (2025-26)
School Full course for CBSE students
₹37,300 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
The flightless birds Rhea Kiwi and Emu respectively class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
