
Equivalent mass of ferrous oxalate in the following reaction is: .
A)
B)
C)
D)
Answer
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Hint: The equivalent mass of an oxidant or reductant is that mass which either supplies or consumes one mole of electrons in a redox reaction.
In a reaction, we can calculate the equivalent mass by using the following relation
For this purpose, we need to first calculate the n factor. n factor gives the number of electrons lost or gained by an oxidant or reductant.
Complete step-by-step solution:
The reaction is the oxidation half reaction in which ferrous oxalate is oxidized to ferric ions and carbon dioxide ions. Increase in the oxidation number is oxidation and decrease in the oxidation number is reduction.
The oxidation number of iron in ferrous oxalate is +2. In ferric ions, the oxidation number of iron is +3. Thus, during the reaction, the oxidation number of iron increases from +2 to +3. Thus, iron is oxidized during the reaction.
Ferrous ion loses a proton to form ferric ion.
Similarly, an oxalate ion loses two electrons to form two molecules of carbon dioxide.
During this reaction, oxalate ion is oxidized to carbon dioxide. Loss of electrons is oxidation and gain of electrons is reduction.
One molecule of ferrous oxalate loses three electrons to form one ferric ion and two carbon dioxide molecules.
Here, the value of n factor is 3.
Equivalent mass of ferrous oxalate in the reaction is
Hence the correct answer is option ‘C’.
Note: In a redox reaction, n factor is the number of electrons that participate in the half reaction. We can also calculate the n factor from the change in the oxidation number.
In a reaction, we can calculate the equivalent mass by using the following relation
For this purpose, we need to first calculate the n factor. n factor gives the number of electrons lost or gained by an oxidant or reductant.
Complete step-by-step solution:
The reaction
The oxidation number of iron in ferrous oxalate
Ferrous ion loses a proton to form ferric ion.
Similarly, an oxalate ion loses two electrons to form two molecules of carbon dioxide.
During this reaction, oxalate ion is oxidized to carbon dioxide. Loss of electrons is oxidation and gain of electrons is reduction.
One molecule of ferrous oxalate
Here, the value of n factor is 3.
Equivalent mass of ferrous oxalate
Hence the correct answer is option ‘C’.
Note: In a redox reaction, n factor is the number of electrons that participate in the half reaction. We can also calculate the n factor from the change in the oxidation number.
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