
Equation of the plane through the midpoint of the line segment joining the points
$P(4,5, - 10),Q( - 1,2,1)$ and perpendicular to $PQ$ is
A. $r.\left( {\dfrac{2}{3}\hat i + \dfrac{7}{2}\hat j - \dfrac{9}{2}\hat k} \right) = 45$
B. $r.\left( { - \hat i + 2\hat j + \hat k} \right) = \dfrac{{135}}{2}$
C. $r.\left( {5\hat i + 3\hat j - 11\hat k} \right) + \dfrac{{135}}{2} = 0$
D. $r.\left( {4\hat i + 5\hat j - 10\hat k} \right) = 85$
E. $r.\left( {5\hat i + 3\hat j - 11\hat k} \right) = \dfrac{{135}}{2}$
Answer
610.8k+ views
Hint:- find midpoint and direction ratio between two points. Use midpoint and direction ratio to solve this question.
Complete step-by-step answer:
Here the given two points are $P(4,5, - 10),Q( - 1,2,1)$
Therefore coordinate of the midpoint of $P$and $Q$is
As we know the midpoint formula between two points is $\left( {\dfrac{{{x_1} + {x_2}}}{2},\dfrac{{{y_1} + {y_2}}}{2},\dfrac{{{z_1} + {z_2}}}{2}} \right)$
$\left( {\dfrac{{4 - 1}}{2},\dfrac{{5 + 2}}{2},\dfrac{{ - 10 + 1}}{2}} \right)$ i.e. $\left( {\dfrac{3}{2},\dfrac{7}{2},\dfrac{{ - 9}}{2}} \right)$
And we know that the direction ratio between two points are $\left( {{x_2} - {x_1},{y_2} - {y_1},{z_2} - {z_1}} \right)$
Now direction ratio of $PQ$ is $\left( { - 1 - 4,2 - 5,1 + 10} \right)$ i.e. is $\left( { - 5, - 3,11} \right)$ or $\left( {5,3, - 11} \right)$
Therefore, equation of plane passing through $\left( {\dfrac{3}{2},\dfrac{7}{2},\dfrac{{ - 9}}{2}} \right)$ and having direction ratio $\left( {5,3, - 11} \right)$ is
$5\left( {x - \dfrac{3}{2}} \right) + 3\left( {y - \dfrac{7}{2}} \right) - 11\left( {z + \dfrac{9}{2}} \right) = 0$
as we know when the point $\left( {{x_1},{y_1},{z_1}} \right)$ and the direction ratio $\left( {{x_2},{y_2},{z_2}} \right)$ are given the equation of line is ${x_2}\left( {x - {x_1}} \right) + {y_2}\left( {y - {y_1}} \right) + {z_2}\left( {z - {z_1}} \right) = 0$
$
\Rightarrow 5x + 3y - 11z = \dfrac{{15}}{2} + \dfrac{{21}}{2} + \dfrac{{99}}{2} \\
\Rightarrow 5x + 3y - 11z = \dfrac{{135}}{2} \\
$
It is written in vector form
$r.\left( {5\hat i + 3\hat j - 11\hat k} \right) = \dfrac{{135}}{2}$
Hence, option E is the correct answer.
Note:- first of all you have to find the midpoint as the plane must pass through the midpoint given in question then for the equation of plane we must have to find the direction ratio between two points then apply the formula of writing the equation of plane. As we know the direction ratio of planes are always perpendicular to the plane.
Complete step-by-step answer:
Here the given two points are $P(4,5, - 10),Q( - 1,2,1)$
Therefore coordinate of the midpoint of $P$and $Q$is
As we know the midpoint formula between two points is $\left( {\dfrac{{{x_1} + {x_2}}}{2},\dfrac{{{y_1} + {y_2}}}{2},\dfrac{{{z_1} + {z_2}}}{2}} \right)$
$\left( {\dfrac{{4 - 1}}{2},\dfrac{{5 + 2}}{2},\dfrac{{ - 10 + 1}}{2}} \right)$ i.e. $\left( {\dfrac{3}{2},\dfrac{7}{2},\dfrac{{ - 9}}{2}} \right)$
And we know that the direction ratio between two points are $\left( {{x_2} - {x_1},{y_2} - {y_1},{z_2} - {z_1}} \right)$
Now direction ratio of $PQ$ is $\left( { - 1 - 4,2 - 5,1 + 10} \right)$ i.e. is $\left( { - 5, - 3,11} \right)$ or $\left( {5,3, - 11} \right)$
Therefore, equation of plane passing through $\left( {\dfrac{3}{2},\dfrac{7}{2},\dfrac{{ - 9}}{2}} \right)$ and having direction ratio $\left( {5,3, - 11} \right)$ is
$5\left( {x - \dfrac{3}{2}} \right) + 3\left( {y - \dfrac{7}{2}} \right) - 11\left( {z + \dfrac{9}{2}} \right) = 0$
as we know when the point $\left( {{x_1},{y_1},{z_1}} \right)$ and the direction ratio $\left( {{x_2},{y_2},{z_2}} \right)$ are given the equation of line is ${x_2}\left( {x - {x_1}} \right) + {y_2}\left( {y - {y_1}} \right) + {z_2}\left( {z - {z_1}} \right) = 0$
$
\Rightarrow 5x + 3y - 11z = \dfrac{{15}}{2} + \dfrac{{21}}{2} + \dfrac{{99}}{2} \\
\Rightarrow 5x + 3y - 11z = \dfrac{{135}}{2} \\
$
It is written in vector form
$r.\left( {5\hat i + 3\hat j - 11\hat k} \right) = \dfrac{{135}}{2}$
Hence, option E is the correct answer.
Note:- first of all you have to find the midpoint as the plane must pass through the midpoint given in question then for the equation of plane we must have to find the direction ratio between two points then apply the formula of writing the equation of plane. As we know the direction ratio of planes are always perpendicular to the plane.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

The computer jargonwwww stands for Aworld wide web class 12 physics CBSE

State the principle of an ac generator and explain class 12 physics CBSE

