
Equation: \[2x - y = 4\] meets
\[x\] axis at \[( - 4,0)\]
\[y\] axis at \[(0,2)\]
\[x\] axis at \[(2,0)\]
\[y\] axis at \[(0, - 4)\]
Answer
558k+ views
Hint: Here, we have to find the values of \[x\] co-ordinate and \[y\] co-ordinate where the given line meets the \[x\] axis and \[y\] axis. We have to find those co-ordinates by using the intercept concept. The point where a curve or a line crosses the axis of the graph is called an intercept. If a point crosses the \[x\]-axis, then it is said to be \[x\]-intercept and if a point crosses the \[y\]-axis, then it is known as \[y\]-intercept.
Complete step-by-step answer:
The Equation \[2x - y = 4\] is an equation of a straight line. The equation of a straight line is of the form \[y = mx + c\] where \[m\] is the slope or the gradient and \[c\] is the \[y\] -intercept.
Now, we will find the \[x\] - intercept.
Substituting \[y = 0\] in the above equation, we get
\[ \Rightarrow 2x - 0 = 4\]
\[ \Rightarrow 2x = 4\]
Dividing both the sides by 2, we get
\[ \Rightarrow x = 2\]
So, the equation meets the \[x\] - axis at \[x = 2\]
Now, we have to find the \[y\] - intercept.
Substituting \[x = 0\] and solving for \[y\] , we have
\[ \Rightarrow 2(0) - y = 4\]
\[ \Rightarrow - y = 4\]
Rewriting the equation, we get
\[ \Rightarrow y = - 4\]
So, the equation meets the \[y\] - axis at \[y = - 4\]
Therefore, the equation \[2x - y = 4\] meets the \[x\] - axis at \[\left( {2,0} \right)\] and the \[y\] - axis at \[\left( {0, - 4} \right)\] .
Note: We can find the \[y\] - intercept from the equation \[2x - y = 4\]. Rewriting the equation as \[y = 2x - 4\] . Since the equation of a straight line is of the form \[y = mx + c\] where \[m\] is the slope or the gradient and \[c\] is the \[y\] -intercept. The slope of a line is defined as the ratio of the amount that \[y\] increases as \[x\] increases some amount. Slope tells us how steep a line is, or how much \[y\] increases as \[x\] increases. We will get the \[x\]-intercept as \[y = - 4\].
Complete step-by-step answer:
The Equation \[2x - y = 4\] is an equation of a straight line. The equation of a straight line is of the form \[y = mx + c\] where \[m\] is the slope or the gradient and \[c\] is the \[y\] -intercept.
Now, we will find the \[x\] - intercept.
Substituting \[y = 0\] in the above equation, we get
\[ \Rightarrow 2x - 0 = 4\]
\[ \Rightarrow 2x = 4\]
Dividing both the sides by 2, we get
\[ \Rightarrow x = 2\]
So, the equation meets the \[x\] - axis at \[x = 2\]
Now, we have to find the \[y\] - intercept.
Substituting \[x = 0\] and solving for \[y\] , we have
\[ \Rightarrow 2(0) - y = 4\]
\[ \Rightarrow - y = 4\]
Rewriting the equation, we get
\[ \Rightarrow y = - 4\]
So, the equation meets the \[y\] - axis at \[y = - 4\]
Therefore, the equation \[2x - y = 4\] meets the \[x\] - axis at \[\left( {2,0} \right)\] and the \[y\] - axis at \[\left( {0, - 4} \right)\] .
Note: We can find the \[y\] - intercept from the equation \[2x - y = 4\]. Rewriting the equation as \[y = 2x - 4\] . Since the equation of a straight line is of the form \[y = mx + c\] where \[m\] is the slope or the gradient and \[c\] is the \[y\] -intercept. The slope of a line is defined as the ratio of the amount that \[y\] increases as \[x\] increases some amount. Slope tells us how steep a line is, or how much \[y\] increases as \[x\] increases. We will get the \[x\]-intercept as \[y = - 4\].
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

