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How is entropy related to the spontaneity of a reaction?

Answer
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Hint: 1)The second law of thermodynamics says that the entropy of the universe consistently increments for an spontaneous process: ΔSuniverse=ΔSsystem+ΔSsurrounding>0
2)A consistent temperature and pressure, the adjustment in Gibbs free energy is defined as
 ΔG=ΔHTΔS
3)The spontaneity of a process can rely upon the temperature

Complete step by step answer:
Entropy (S) is a proportion of the disorder in a system.
In a closed system, entropy consistently increases after some time. In an open system, energy can be added to a system to cause a lessening in entropy, however this isn't really a spontaneous reaction.
In the event that entropy (disorder) increases, and the reaction enthalpy is exothermic (ΔH<0) or
pitifully endothermic (ΔH>0 and small), the reaction is for the most part spontaneous.
The Gibbs free energy condition is:
ΔG=ΔHTΔS
A reaction will be spontaneous if the adjustment in G, ΔG , is negative.
For the result of temperature times ΔS , whereΔS is the change in entropy, if the change in entropy is positive (disorder increases), then TδS, when subtracted, gets negative.
Since the cosmos (discernible universe) is basically a closed system, entropy will keep on expanding until the universe basically stops to exist.

Note: When ΔG<0 , the process is exergonic and will continue spontaneously the forward direction to form more products.
When ΔG>0 , the process is endergonic and not spontaneous in the forward direction. All things being equal, it will continue spontaneously in the opposite direction to make more beginning materials.
When ΔG=0 , the system is in equilibrium and the concentrations of the products and reactants will stay consistent.
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