Question

What is the element in group $4$ and period $4$ ?

Answer 1

Hint: Group $4$ elements are the transition elements. It is the second group of elements. Periods $4$ elements start with potassium and end with krypton. Name all the elements of both group $4$ and period $4$ then we will have the required element.

Complete answer: The modern periodic table consists of groups and periods. All the elements are arranged in order of increasing atomic number in these groups and periods. There are seven periods and eighteen groups in total for the known elements till now. Group $4$ is the second group of transition elements. Transition elements are generally the $d - $ block elements. Group $4$ elements are titanium, zirconium, hafnium and rutherfordium. These are the four elements of Group $4$ .Also by looking in the modern periodic table we can represent group $4$ elements as:
Group $4$
Titanium $\left( {Ti} \right)$
Zirconium $\left( {Zr} \right)$
Hafnium $\left( {Hf} \right)$
Rutherfordium $\left( {Rf} \right)$
Hence we can find out the period $4$ elements too. Period $4$ elements start from potassium and end at krypton. Periods $4$ elements contain potassium, calcium, scandium, titanium, vanadium, chromium, manganese, iron, cobalt, nickel, copper, zinc and end at krypton.
Period $4$ : Potassium $\left( K \right)$ Calcium $\left( {Ca} \right)$ Scandium $\left( {Sc} \right)$ Titanium $\left( {Ti} \right)$ …… krypton $\left( {Kr} \right)$
Therefore we can find out the element which is present in period $4$ and group $4$ .
- Titanium $\left( {Ti} \right)$
Thus Titanium is the transition element which is present in period $4$ and group $4$ .

Note:
We can find out the element by writing the general electronic configuration of period $4$ elements and group $4$ elements and thus we get the required element. Period $4$ contains eighteen elements out of which only few are mentioned above. Group $4$ contains four elements.