Question

Draw the ray diagram and also state the position, relative size and nature of the image formed by a concave mirror when the object is placed between its center of curvature, C and the focus F.

Answer 1

Hint:In order to draw the ray diagram of concave mirror first. See the location of the object which is given in question.According to position of object given first, see that object is real or virtual. After that we draw a concave mirror and object and incident a ray from object to mirror and draw the image and see whether it will be magnified or not and erect are inverted.

Complete step by step answer:
Given that object is placed between the center of converter C and focus F. We can easily understand that the property of a concave mirror object is real. Now, we can draw the ray diagram by incident ray from object to mirror.

Here
P $ = $ pole
F $ = $ focus of mirror
C $ = $ center of curvature
AB $ = $ length of object
${A^1}{B^1}$ $ = $ length of image
Here, we can see in a ray diagram.
Position of image: Beyond the Centre of curvature
Size of image: Magnified
Nature of image: Real and inverted

Hence, we can conclude that if the object is real and placed between focus F and center of curvature C then image will be formed beyond the center of curvature and real inverted and magnified.

Note: In order to solve the mirror problem, we have to know about the type of mirrors and their characteristics. And also remember that the ray that passes through the center of curvature of the mirror will retrace its own path in the opposite direction.