
Draw a percentage bar graph for the following data:
Divisions A B C D Total strength 65 56 54 50 students passed in English 36 42 27 23
Divisions | A | B | C | D |
Total strength | 65 | 56 | 54 | 50 |
students passed in English | 36 | 42 | 27 | 23 |
Answer
502.8k+ views
Hint: We first determine the formula to find the percentage of students passed in English. We take given data as two variables and find the percentages. Then we place them in a percentage bar graph to find out the illustration.
Complete step by step answer:
We find the percentage formula for the students who passed in English.
We are taking two variables x and y. x being the number of students passed in English in a single division and y being the total strength in that same division.
So, there are four divisions named A, B, C, D.
We find the percentage theorem as where .
For division A the percentage is .
For division B the percentage is .
For division C the percentage is .
For division D the percentage is .
Now we make a table to illustrate this
We place the data to find the percentage bar
Note:
Percentage bar graph is used to find the comparison. The data of a single variable should be put under a single bar. We can also relate it with the numbers of students failing the English examination.
Complete step by step answer:
We find the percentage formula for the students who passed in English.
We are taking two variables x and y. x being the number of students passed in English in a single division and y being the total strength in that same division.
So, there are four divisions named A, B, C, D.
We find the percentage theorem as
For division A the percentage is
For division B the percentage is
For division C the percentage is
For division D the percentage is
Now we make a table to illustrate this
Divisions | total strength(y) | students passed in English(x) | percentages (%) |
A | 65 | 36 | 55.38 |
B | 56 | 42 | 75 |
C | 54 | 27 | 50 |
D | 50 | 23 | 46 |
We place the data to find the percentage bar

Note:
Percentage bar graph is used to find the comparison. The data of a single variable should be put under a single bar. We can also relate it with the numbers of students failing the English examination.
Latest Vedantu courses for you
Grade 9 | ICSE | SCHOOL | English
Vedantu ICSE 9 Pro Course (2025-26)
School Full course for ICSE students
₹37,300 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE

Give two reasons to justify a Water at room temperature class 11 chemistry CBSE
