Question

Draw a labeled diagram of the experiment explaining Ohm's Law.

Answer 1

Hint: Ohm’s law provides the relationship between supplied voltage and flow of current through a circuit that has some amount of resistance.

Complete step by step solution:
Ohm’s law states that the current flowing through a conductor between two points is directly proportional to the voltage across those two points. Mathematically:
$I={\displaystyle \frac{V}{R}}$
Where,
$I$ denote the amount of current flowing,
$V$ denotes the amount of voltage applied,
$R$ is the resistance of the conductor.

Explanation:
Here, the closed-circuit has a power source (battery) which is supplying a voltage $V$. There is a Resistor of resistance $R$ at the other end of the circuit. When the key is closed a steady current $I$ flows through the circuit. There is an ammeter $A$ connected in series with the circuit to measure the amount of current flowing through the resistor. There is also a voltmeter $V$ connected parallel across the resistor to measure the potential difference across it.
Now, as this circuit obeys Ohm’s law, you’ll get the relationship as $V=I.R$.
To verify it through an experiment, you have to vary the voltage $V$ in regular intervals and take the corresponding values of current in the circuit.
Now, if you plot the data points in a graph paper keeping Voltage values ($V$) in the y-axis and current values($I$) in the x-axis then you will get a straight line connecting those data points. This straight line will have a slope the same as $R$.

Hence, Ohm’s law will be verified by a simple experiment.

Note:
Here, all the components are assumed to be ideal i.e. all including the battery, wires, and ammeter have zero internal resistance where the voltmeter has infinite resistance so that no current passes through it. In practice, nothing is ideal. So, we can verify Ohm’s law only within some error limits.