
How does hybridization affect electronegativity?
Answer
543.9k+ views
Hint: The inclination of a molecule to pull in holding electrons towards itself is called its electronegativity.
The more noteworthy the s-character of the half and half orbitals, the more prominent is the electronegativity on the grounds that a s orbital holds electrons all the more firmly to the core
Regarding Electronegativity: \[sp{\text{ }} > {\text{ }}s{p^2} > {\text{ }}s{p^3}\]
Complete step by step answer:
Electronegativity increments with the s-character of the half and half orbital utilized for making covalent bond.
It could be clarified by taking a straightforward illustration of three least difficult hydrocarbons
Ethane \[{C_2}{H_6}\]→ where \[C\] uses- \[s{p^3}\] hybrid orbital with \[25\% \] s-Character
Ethene \[{C_2}{H_4}\]→ where \[C\] uses-\[s{p^2}\] hybrid orbital with \[33.33\% \] s-Character
Ethyne \[{C_2}{H_2}\]→ where \[C\] uses-\[sp\] hybrid orbital with half s-Character
S orbital being the orbital nearer to the \[C\]-atom the electron pair of the bond shaped by the orbital having higher s-character is pulled in addition towards \[C\]-particle indicating higher electronegativity .
Along these lines the request for EN of Carbon
\[Ethyne > Ethene > Ethane\]
The electronegativity of carbon relies upon its hybridization state. Carbons that are \[s{p^2}\] - hybridized are fairly more electronegative than \[s{p^3}\] - hybridized carbons; sp-hybridized carbons are much more electronegative by another \[0.2\] units. This implies that \[s{p^3}-{\text{ }}s{p^2}\] carbon–carbon bonds have a slight bond dipole.
Bond-strength impacts and electronegativity impacts. The request can't be a bond-strength impact, since bond qualities increment with expanding s character. That is, the strength of a \[C\left( {sp} \right)--{\text{ }}H\] bond is more prominent than that of a \[C\left( {s{p^2}} \right)--{\text{ }}H\] bond, which is more noteworthy than that of a \[\;C\left( {s{p^3}} \right)--{\text{ }}H\] bond. Hence, this should be an electronegativity impact. This corrosiveness request, at that point, is reliable with expanding electronegativity of carbons with expanding s character in their hybridizations.
Note:
Three kinds of hybridisation − \[sp\], \[s{p^2}\] and \[s{p^3}\], are found in carbon particles relying on the number of atoms connected to the carbon.
A \[sp\] hybrid orbital has half s-character and half p-character; a \[s{p^2}\] hybrid orbital has \[33.33\% \]s-character and \[66.66\% \] p-character; a \[s{p^3}\] hybrid orbital has \[25\% \] s-character and \[75\% \] p-character.
The more noteworthy the s-character of the half and half orbitals, the more prominent is the electronegativity on the grounds that a s orbital holds electrons all the more firmly to the core
Regarding Electronegativity: \[sp{\text{ }} > {\text{ }}s{p^2} > {\text{ }}s{p^3}\]
Complete step by step answer:
Electronegativity increments with the s-character of the half and half orbital utilized for making covalent bond.
It could be clarified by taking a straightforward illustration of three least difficult hydrocarbons
Ethane \[{C_2}{H_6}\]→ where \[C\] uses- \[s{p^3}\] hybrid orbital with \[25\% \] s-Character
Ethene \[{C_2}{H_4}\]→ where \[C\] uses-\[s{p^2}\] hybrid orbital with \[33.33\% \] s-Character
Ethyne \[{C_2}{H_2}\]→ where \[C\] uses-\[sp\] hybrid orbital with half s-Character
S orbital being the orbital nearer to the \[C\]-atom the electron pair of the bond shaped by the orbital having higher s-character is pulled in addition towards \[C\]-particle indicating higher electronegativity .
Along these lines the request for EN of Carbon
\[Ethyne > Ethene > Ethane\]
The electronegativity of carbon relies upon its hybridization state. Carbons that are \[s{p^2}\] - hybridized are fairly more electronegative than \[s{p^3}\] - hybridized carbons; sp-hybridized carbons are much more electronegative by another \[0.2\] units. This implies that \[s{p^3}-{\text{ }}s{p^2}\] carbon–carbon bonds have a slight bond dipole.
Bond-strength impacts and electronegativity impacts. The request can't be a bond-strength impact, since bond qualities increment with expanding s character. That is, the strength of a \[C\left( {sp} \right)--{\text{ }}H\] bond is more prominent than that of a \[C\left( {s{p^2}} \right)--{\text{ }}H\] bond, which is more noteworthy than that of a \[\;C\left( {s{p^3}} \right)--{\text{ }}H\] bond. Hence, this should be an electronegativity impact. This corrosiveness request, at that point, is reliable with expanding electronegativity of carbons with expanding s character in their hybridizations.
Note:
Three kinds of hybridisation − \[sp\], \[s{p^2}\] and \[s{p^3}\], are found in carbon particles relying on the number of atoms connected to the carbon.
A \[sp\] hybrid orbital has half s-character and half p-character; a \[s{p^2}\] hybrid orbital has \[33.33\% \]s-character and \[66.66\% \] p-character; a \[s{p^3}\] hybrid orbital has \[25\% \] s-character and \[75\% \] p-character.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

