
How does gravity decrease with increased altitude?
Answer
502.5k+ views
Hint: Gravitational forces are the central forces, which is the force that holds down on the Earth and stops us from flying up in space. The universe’s fundamental forces that dominate every moment of our conscious existence is called gravity. His story of gravity goes with the study of physics.
Complete step-by-step solution:
Gravitational forces are the central force, which implies that any two particles, along the line connecting their mass centres, is the gravitational force between any two particles. Also, since the sphere’s surface increases with\[{r^2}\]. The ‘\[r\]’ is the radius. Over the sphere’s surface the gravitational field must be uniformly distributed. The gravitational field is proportional to \[\dfrac{1}{{{R^2}}}\]. Consider the radius of the Earth at the equator to be \[6400km\]. If an aeroplane flies at a distance of 40km above the Earth’s surface then the gravity, \[{g_2}\] is calculated by equating the ratio of acceleration due to gravity, \[{g_1}\] and \[{g_2}\] to square of the ratio of the radius. This gives \[{g_2}\] as \[9.67\dfrac{m}{{{s^2}}}\]. Therefore, it can be said that the gravitational force decreases by the \[1.2\% \] for an aeroplane which is flying at \[40km\]distance.
Note: Earth’s gravity comes from its entire mass. On our body mass, a combined gravitational force pull creates as soon as the earth’s entire mass. Gravitational force is the force of the gravity that keeps all the planets in the orbits around the sun.
Complete step-by-step solution:
Gravitational forces are the central force, which implies that any two particles, along the line connecting their mass centres, is the gravitational force between any two particles. Also, since the sphere’s surface increases with\[{r^2}\]. The ‘\[r\]’ is the radius. Over the sphere’s surface the gravitational field must be uniformly distributed. The gravitational field is proportional to \[\dfrac{1}{{{R^2}}}\]. Consider the radius of the Earth at the equator to be \[6400km\]. If an aeroplane flies at a distance of 40km above the Earth’s surface then the gravity, \[{g_2}\] is calculated by equating the ratio of acceleration due to gravity, \[{g_1}\] and \[{g_2}\] to square of the ratio of the radius. This gives \[{g_2}\] as \[9.67\dfrac{m}{{{s^2}}}\]. Therefore, it can be said that the gravitational force decreases by the \[1.2\% \] for an aeroplane which is flying at \[40km\]distance.
Note: Earth’s gravity comes from its entire mass. On our body mass, a combined gravitational force pull creates as soon as the earth’s entire mass. Gravitational force is the force of the gravity that keeps all the planets in the orbits around the sun.
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