
Does benzene dissolve in water?
Answer
488.7k+ views
Hint: The organic chemical compound benzene has the molecular formula ${C_6}{H_6}$. The benzene molecule is made up of six carbon atoms arranged in a planar ring, each containing one hydrogen atom. Benzene is classified as a hydrocarbon because it exclusively contains carbon and hydrogen atoms.
Complete answer:
At ${15^0}C$, benzene has a solubility of $1.79g/L$ that is about $0.02$$0.02mol/L$, it shows benzene has some water solubility. However, many chemists use $0.10mol/L$ as the high/low solubility cut-off point. Benzene is insoluble in water according to this definition.
Water is a polar compound with dipole moment, whereas benzene is a symmetrical compound with zero dipole moment and so is non-polar.
When benzene is mixed with water, the molecular attraction increases, and the benzene molecules are no longer able to interact with the water molecules. As a result, it is insoluble.
In benzene, the carbon and hydrogen atoms are equally spaced, resulting in a balanced net charge. The net dipole moment is $0$
As a result, mixing the charged and uncharged liquids is impossible, resulting in a failure.
Note:
When compared to a water molecule, benzene is quite big. To dissolve, benzene would have to break a large number of the hydrogen bonds that exist between the water molecules. Furthermore, the van der Waals dispersion forces between the benzene molecules would have to be broken; both of these processes would need energy. Van der Waals dispersion forces would be the only new forces between the benzene and the water. Because these forces are weaker than hydrogen bonds, only a little amount of energy is lost when they develop.
Complete answer:
At ${15^0}C$, benzene has a solubility of $1.79g/L$ that is about $0.02$$0.02mol/L$, it shows benzene has some water solubility. However, many chemists use $0.10mol/L$ as the high/low solubility cut-off point. Benzene is insoluble in water according to this definition.
Water is a polar compound with dipole moment, whereas benzene is a symmetrical compound with zero dipole moment and so is non-polar.
When benzene is mixed with water, the molecular attraction increases, and the benzene molecules are no longer able to interact with the water molecules. As a result, it is insoluble.
In benzene, the carbon and hydrogen atoms are equally spaced, resulting in a balanced net charge. The net dipole moment is $0$
As a result, mixing the charged and uncharged liquids is impossible, resulting in a failure.
Note:
When compared to a water molecule, benzene is quite big. To dissolve, benzene would have to break a large number of the hydrogen bonds that exist between the water molecules. Furthermore, the van der Waals dispersion forces between the benzene molecules would have to be broken; both of these processes would need energy. Van der Waals dispersion forces would be the only new forces between the benzene and the water. Because these forces are weaker than hydrogen bonds, only a little amount of energy is lost when they develop.
Recently Updated Pages
Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Plot a graph between potential difference V and current class 12 physics CBSE

