Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Distance of the center of mass of a solid uniform cone from its vertex is z0. If the radius of its base is R and its height is ‘h’ then z0 is equal to:
Ah24RB3h4C5h4D3h28R

Answer
VerifiedVerified
513.9k+ views
like imagedislike image
- Hint: The center of a solid body can be calculated by taking a suitable cross-section in the body, applying it in the center of mass formula for continuous bodies and integrating it throughout to get the center of mass.

Complete step-by-step solution -
In this question we are given a solid uniform cone of radius R and height h, we need to find the center of mass from the vertex. Given below is a rough diagram of the solid cone.
seo images


We will consider a small circular cross-section of radius ‘z’ and thickness ‘dr’ from a distance ‘r’ from the vertex of the solid cone.
Consider two triangles ABC and AOD. These triangles are similar triangles, so we can write,
ABAO=BCOD
Which can be expressed as,
rh=zR …… equation (1)
The volume of the small volume element considered is given by, dV=πz2dr, which can be written in terms of r using equation (1). So we get,
dV=πR2r2h2dr …. equation (2)
The center of mass for continuous mass distribution is given by the formula,
C.M=1Mrdm
Where,
M is the mass of the circular cone.
dm is the mass of the small element we are considering.
The small mass dm can be written as dm=ρdV. ρ is the volume density of the solid cone.
Therefore, we can write
C.M=1MrρπR2r2h2drC.M=πR2ρMh2r3dr
The limits of the integration are from zero to h, so we can write,
C.M=πR2ρMh20hr3dr
Integrating and applying the limits we will get,
C.M=ρR2πh24M

Substituting M as M= ρ V= ρ (1/3 π R2h), we can write
C.M=3h4
So the answer to the question is option (B) 3h4

Note: The distance to the center of mass from point O is h4.
The center of mass of the cone will always lie on its axis due to symmetry.
The center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.