
How do you determine whether the ratios are equivalent: $3/4,24/32$ ?
Answer
547.2k+ views
Hint: We have been asked to verify whether the ratios of the given terms are equal or not $3/4,24/32$ . For doing that we will verify the ratio by simplifying the second term and comparing it with the first term.
Complete step-by-step solution:
Now considering from the question we have been asked to verify whether the ratios of the given terms $3/4,24/32$ is equal or not.
For doing that we will verify the ratio by simplifying the second term which is $24/32$ and comparing it with the first term which is $3/4$ .
So here we need to verify the ratio between different consecutive terms.
We will verify the ratio of $3/4,24/32$. The simplified form of $24/32$ is $\Rightarrow 24/32=3/4$ .
If we observe all the ratios are equal. Therefore these terms $3/4,24/32$ have a common ratio.
Since the given two terms have a common ratio we can say that they are part of a geometric sequence.
Note: This type of questions are very simple, involve less calculations, very few mistakes are possible and can be solved in a less span of time. We can also find the ${{n}^{th}}$ term of the sequence by using the formula given as $a{{r}^{n-1}}$ where $a$ is the first term and $r$ is the common ratio. If we assume that the given terms are first two terms of the sequence then ${{n}^{th}}$ term will be given as $\Rightarrow \left( 3/4 \right){{\left( 3/4 \right)}^{n-1}}$ .
Complete step-by-step solution:
Now considering from the question we have been asked to verify whether the ratios of the given terms $3/4,24/32$ is equal or not.
For doing that we will verify the ratio by simplifying the second term which is $24/32$ and comparing it with the first term which is $3/4$ .
So here we need to verify the ratio between different consecutive terms.
We will verify the ratio of $3/4,24/32$. The simplified form of $24/32$ is $\Rightarrow 24/32=3/4$ .
If we observe all the ratios are equal. Therefore these terms $3/4,24/32$ have a common ratio.
Since the given two terms have a common ratio we can say that they are part of a geometric sequence.
Note: This type of questions are very simple, involve less calculations, very few mistakes are possible and can be solved in a less span of time. We can also find the ${{n}^{th}}$ term of the sequence by using the formula given as $a{{r}^{n-1}}$ where $a$ is the first term and $r$ is the common ratio. If we assume that the given terms are first two terms of the sequence then ${{n}^{th}}$ term will be given as $\Rightarrow \left( 3/4 \right){{\left( 3/4 \right)}^{n-1}}$ .
Recently Updated Pages
Master Class 7 English: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Master Class 7 Science: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
What are the factors of 100 class 7 maths CBSE

The value of 6 more than 7 is A 1 B 1 C 13 D 13 class 7 maths CBSE

Convert 200 Million dollars in rupees class 7 maths CBSE

What were the major teachings of Baba Guru Nanak class 7 social science CBSE

Find the largest number which divides 615 and 963 leaving class 7 maths CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE


