
Determine the graph of the equation \[y = 2x - 3\] ?
Answer
483.6k+ views
Hint: To determine the graph we need different \[x\] values as well as their corresponding values of \[y\]. To solve this question, we take any value of \[x\] and then find the corresponding value of \[y\] and vice versa. In this way, we find two points and plot them on the graph and join them in order to get the graph of the equation.
Complete answer:
Given equation is \[y = 2x - 3\]
To plot a graph of the given equation \[y = 2x - 3\], we need points.
To find the first point let us put \[x = 0\] and find the corresponding value of \[y\].
On putting the value \[x = 0\] in the given equation.
\[y = 2 \times 0 - 3\]
On simplifying we get the value of \[y\]
\[ \Rightarrow y = - 3\]
This means when $x=0$, the value of $y$ on the graph is $-3$. On observing the values of \[x\] and \[y\] we get the first point.
\[A\] be the first point. \[A = \left( {0, - 3} \right)\]
To find the second point we put \[y = 0\] and find the corresponding value of \[x\].
On putting the value \[y = 0\] in the given equation.
\[0 = 2 \times x - 3\]
On taking 3 to another side
\[2 \times x = 3\]
On simplifying we get the value of \[x\]
\[ \Rightarrow x = \dfrac{3}{2}\]
\[ \Rightarrow x = 1.5\]
On observing the values of \[x\] and \[y\] we get the second point.
\[B\] be the first point. \[B = \left( {1.5,0} \right)\]
Now we make a table of these points.
Now we put these points in the graph and join them to obtain the graph of the equation.
On putting these points in the graph. The graph looks like-
Note:
To plot the graph of the linear equation we need a minimum of two points but we are unable to make a line with a single point. More points are required if we make a curve then more points are required and with more points, our curve is more accurate.
Complete answer:
Given equation is \[y = 2x - 3\]
To plot a graph of the given equation \[y = 2x - 3\], we need points.
To find the first point let us put \[x = 0\] and find the corresponding value of \[y\].
On putting the value \[x = 0\] in the given equation.
\[y = 2 \times 0 - 3\]
On simplifying we get the value of \[y\]
\[ \Rightarrow y = - 3\]
This means when $x=0$, the value of $y$ on the graph is $-3$. On observing the values of \[x\] and \[y\] we get the first point.
\[A\] be the first point. \[A = \left( {0, - 3} \right)\]
To find the second point we put \[y = 0\] and find the corresponding value of \[x\].
On putting the value \[y = 0\] in the given equation.
\[0 = 2 \times x - 3\]
On taking 3 to another side
\[2 \times x = 3\]
On simplifying we get the value of \[x\]
\[ \Rightarrow x = \dfrac{3}{2}\]
\[ \Rightarrow x = 1.5\]
On observing the values of \[x\] and \[y\] we get the second point.
\[B\] be the first point. \[B = \left( {1.5,0} \right)\]
Now we make a table of these points.
| \[x\] | \[y\] |
| 0 | -3 |
| 1.5 | 0 |
Now we put these points in the graph and join them to obtain the graph of the equation.
On putting these points in the graph. The graph looks like-
Note:
To plot the graph of the linear equation we need a minimum of two points but we are unable to make a line with a single point. More points are required if we make a curve then more points are required and with more points, our curve is more accurate.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

