Question

Describe an experiment in detail to prepare $1{\text{ molar}}$ ${\text{NaOH}}$ a solution.

Answer 1

Hint: To prepare the $1{\text{ molar}}$ ${\text{NaOH}}$ solution one needs to calculate the values which are needed to calculate the molarity of a solution. The values such as the molar mass of solute are needed to put into the equation of molarity. While preparing the molar volume one must remember that the volume is always taken one liter and should be applied while making a solution.

Complete step by step answer:
- First of all let's know about the concept of molarity where it is the amount of a substance that is present in a certain volume of solution and can be defined as the moles of a solute per liters of a solution.
- Now, let's head towards the experiment to prepare $1{\text{ molar}}$ ${\text{NaOH}}$ a solution where the first step is to dissolve the molar mass of ${\text{NaOH}}$ which we need to find out by adding the atomic mass of each element.
${\text{Molar mass of NaOH = 1}} \times {\text{Na + 1}} \times {\text{O + 1}} \times H = 23 + 16 + 1 = 40{\text{ grams}}$
- Now in the next step dissolve the molar mass of ${\text{NaOH}}$ which is $40{\text{ grams}}$ using distilled water in a beaker. Afterward, transfer this dissolved solution to a one-liter volumetric flask and rinse the beaker several times with distilled water and put it in the volumetric flask, and at last, fill the volumetric flask with distilled water up to the mark of one liter.
-Therefore, the formed solution is $1{\text{ molar}}$ ${\text{NaOH}}$ solution.

Note: For the calculation of the exact molarity of ${\text{NaOH}}$ one must standardize it with a primary standard material like potassium hydrogen phthalate which is also known as KHP. The potassium hydrogen phthalate solution is called a secondary standard solution and this method is used to know the exact molarity of ${\text{NaOH}}$ solution.