
Derive a relation between the Celsius and Fahrenheit scales of temperature using the fixed point in two different scales.
Answer
579.6k+ views
Hint: We know that the two scales used for temperature measurements are Celsius and Fahrenheit. We also know that the temperature in the centigrade scale will be expressed in degrees Celsius. So, we find the relationship and then derive the above statement to correct two separate scales.
Formula used:
Celsius to Fahrenheit,
$F = \left( {\dfrac{9}{5} \times C} \right) + 32$
Fahrenheit to Celsius,
$C = \dfrac{5}{9}\left( {F - 32} \right)$
Where,
$F$ is the temperature in Fahrenheit,
$C$ is the temperature on the centigrade scale.
Complete step-by-step solution:
Given by,
The relation between the Celsius and Fahrenheit scales,
The Celsius-Fahrenheit relationship is direct. Celsius is specifically linked to Fahrenheit.
Which suggests that
As the temperature rises on the Celsius scale, the equivalent temperature of Fahrenheit would also be high.
As the temperature falls on the Celsius scale, the temperature equal to Fahrenheit would also be low.
$\dfrac{{C - L.F.P}}{{U.F.P - L.F.P}} = \dfrac{{F - L.F.P}}{{U.F.P - L.F.P}}$
Here, we define,
$L.F.P$ is Lower Fixed Point
$U.F.P$ is Upper Fixed Point
According to that,
$\dfrac{{C - 0}}{{100 - 0}} = \dfrac{{F - 32}}{{212 - 32}}$
On simplifying,
We get,
$\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$
Again, we resolve the above equation,
We get,
$\dfrac{C}{5} = \dfrac{{\left( {F - 32} \right)}}{9}$
A temperature scale based on the freezing point of water at ${0^ \circ }C$ and the boiling point of water at ${100^ \circ }C$ is the Celsius scale, or centigrade scale. The Fahrenheit scale is a temperature scale based on the ${32^ \circ }F$ water freezing point and the ${220^ \circ }F$ water boiling point.
Hence,
Thus, the Celsius and Fahrenheit scales of temperature using the fixed point in two different scales $\dfrac{C}{5} = \dfrac{{\left( {F - 32} \right)}}{9}$
Note: The above derivation is evaluating the relation between Celsius and Fahrenheit is proportional. Both have different freezing points of water and both follow the varied unit difference between each scale. That is because of the Celsius temperature scale, part of the metric system that denotes the temperature.
Formula used:
Celsius to Fahrenheit,
$F = \left( {\dfrac{9}{5} \times C} \right) + 32$
Fahrenheit to Celsius,
$C = \dfrac{5}{9}\left( {F - 32} \right)$
Where,
$F$ is the temperature in Fahrenheit,
$C$ is the temperature on the centigrade scale.
Complete step-by-step solution:
Given by,
The relation between the Celsius and Fahrenheit scales,
The Celsius-Fahrenheit relationship is direct. Celsius is specifically linked to Fahrenheit.
Which suggests that
As the temperature rises on the Celsius scale, the equivalent temperature of Fahrenheit would also be high.
As the temperature falls on the Celsius scale, the temperature equal to Fahrenheit would also be low.
$\dfrac{{C - L.F.P}}{{U.F.P - L.F.P}} = \dfrac{{F - L.F.P}}{{U.F.P - L.F.P}}$
Here, we define,
$L.F.P$ is Lower Fixed Point
$U.F.P$ is Upper Fixed Point
According to that,
$\dfrac{{C - 0}}{{100 - 0}} = \dfrac{{F - 32}}{{212 - 32}}$
On simplifying,
We get,
$\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$
Again, we resolve the above equation,
We get,
$\dfrac{C}{5} = \dfrac{{\left( {F - 32} \right)}}{9}$
A temperature scale based on the freezing point of water at ${0^ \circ }C$ and the boiling point of water at ${100^ \circ }C$ is the Celsius scale, or centigrade scale. The Fahrenheit scale is a temperature scale based on the ${32^ \circ }F$ water freezing point and the ${220^ \circ }F$ water boiling point.
Hence,
Thus, the Celsius and Fahrenheit scales of temperature using the fixed point in two different scales $\dfrac{C}{5} = \dfrac{{\left( {F - 32} \right)}}{9}$
Note: The above derivation is evaluating the relation between Celsius and Fahrenheit is proportional. Both have different freezing points of water and both follow the varied unit difference between each scale. That is because of the Celsius temperature scale, part of the metric system that denotes the temperature.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Which among the following are examples of coming together class 11 social science CBSE

Can anyone list 10 advantages and disadvantages of friction

