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What is the derivative of sin(ax), where a is a constant ?

Answer
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Hint: Here we are given a trigonometric functionsin(ax). We have to find the derivative of this function. Since we have to derivate it with respect to x but function is ax. So to derivate this trigonometric function we apply chain rule. Here two functions on which chain rule will be applied will be sin(x) and ax.

Formula used: Derivative of sin(x) with respect to x is given by ddxsin(x)=cosx.
Derivative of x with respect to x is given by ddxx=1.
To derivate the trigonometric function having if we are given two functions f and g with respect to x we apply chain rule as
ddxf(g(x))=f(g(x))g(x).

Complete step-by-step answer:
To solve the given trigonometric function we have to apply chain rule. According to chain rule, if we are given two functions f and g then we find ddxf(g(x)) as, ddxf(g(x))=f(g(x))g(x). Let f(x)=sinx and g(x)=ax, then
ddxsin(ax)=dsin(ax)d(ax)×d(ax)dx
Since we know that the derivative of sin(x) with respect to x is given by ddxsin(x)=cosx and derivative of x with respect to x is equal to 1, we proceed to further steps using above mentioned formulas as,
ddxsin(ax)=dsin(ax)d(ax)×adxdxddxsin(ax)=cos(ax)×addxsin(ax)=acos(ax)
Hence, the derivative of the given trigonometric function comes out to be acos(ax).

Note: This is to note that derivative of constant with respect to any variable is zero. Chain rule we have used here is a way to differentiate composite functions. Differentiation is a method or process of finding the derivative or rate of change of a function. Here we have found the rate of change of sin(ax) with respect to x.


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