
What is the density of water in \[kg{m^{ - 3}}\]?
A. \[1\]
B. \[1000\]
C. \[100\]
D. \[10000\]
Answer
506.4k+ views
Hint: We have to know that the water is a chemical compound having the chemical formula, \[{H_2}O\]. And the water is an inorganic compound which does not have any taste and odor. And the water is a volatile liquid which is transparent in nature. The particles present in the liquid are far apart. The density of a substance expresses the relationship between and the volume. Hence, it can find out by dividing the mass of a substance with its volume.
Complete answer:
The density of water in \[kg{m^{ - 3}}\] is not equal to\[1\]. Hence, the option (A) is incorrect.
The density of water in \[kg{m^{ - 3}}\] is equal to \[1000\].
The density of a substance is calculated by using the equation,
\[density = \dfrac{{mass}}{{volume}}\]
Here, the unit of the mass is equal to g and the unit of the volume is equal to \[c{m^3}\]. Hence, to find out the density of water in\[kg{m^{ - 3}}\], we have to convert these g and \[c{m^3}\] in to kg and\[{m^3}\]respectively. That is,
\[\left( {1g/c{m^3}} \right)\left( {0.001kg/g} \right)\left( {100cm/{m^3}} \right) = 100g/{m^3}\]
Hence, option (B) is correct.
The density of water in \[kg{m^{ - 3}}\] is not equal to \[100\]. Hence, option (C) is incorrect.
When it is converted to \[kg/{m^3}\], the density of water will not get as \[10000\]. Hence, option (D) is incorrect.
So, the correct answer is “Option B”.
Note:
The density is always mentioned with the temperature. Because, the density always varies with the temperature. At \[{4^o}C\], the maximum density of water will become \[1000kg/{m^3}\]. The density is expressed in terms of mass and volume. Hence, the density is the term which is used to represent the distribution of quantity, it may be mass, energy or electricity.
Complete answer:
The density of water in \[kg{m^{ - 3}}\] is not equal to\[1\]. Hence, the option (A) is incorrect.
The density of water in \[kg{m^{ - 3}}\] is equal to \[1000\].
The density of a substance is calculated by using the equation,
\[density = \dfrac{{mass}}{{volume}}\]
Here, the unit of the mass is equal to g and the unit of the volume is equal to \[c{m^3}\]. Hence, to find out the density of water in\[kg{m^{ - 3}}\], we have to convert these g and \[c{m^3}\] in to kg and\[{m^3}\]respectively. That is,
\[\left( {1g/c{m^3}} \right)\left( {0.001kg/g} \right)\left( {100cm/{m^3}} \right) = 100g/{m^3}\]
Hence, option (B) is correct.
The density of water in \[kg{m^{ - 3}}\] is not equal to \[100\]. Hence, option (C) is incorrect.
When it is converted to \[kg/{m^3}\], the density of water will not get as \[10000\]. Hence, option (D) is incorrect.
So, the correct answer is “Option B”.
Note:
The density is always mentioned with the temperature. Because, the density always varies with the temperature. At \[{4^o}C\], the maximum density of water will become \[1000kg/{m^3}\]. The density is expressed in terms of mass and volume. Hence, the density is the term which is used to represent the distribution of quantity, it may be mass, energy or electricity.
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