What is the density of chlorine gas at $1.21{\text{atm}}$ and $34.9$ degree Celsius.
Answer
581.1k+ views
Hint: The term ideal gas alludes to a theoretical gas made out of atoms that observe a couple of rules: Ideal gas particles don't pull in or repulse one another. The lone communication between ideal gas particles would be a flexible crash upon sway with one another or a versatile impact with the dividers of the compartment.
Complete step by step answer:
We have to know that the ideal gas behavior, then the ideal gas behavior formula has to be used.
Given details,
$P = 1.21{\text{atm}}$
The unit of the temperature is converted into celsius into kelvin,
$T = 34.9^\circ C = 307.9K$
By using the following formula,
$PV = nRT$
Then, we have to rewrite the above equation,
$\dfrac{n}{V} = \dfrac{P}{{RT}}$
Where,
$R = 0.0821{\text{ L}}{\text{.atm/}}{{\text{K}}^{ - 1}}mo{l^{ - 1}}$
Applying all the values in the above equation,
$\dfrac{n}{V} = \dfrac{{1.21{\text{ atm}}}}{{(0.0821{\text{ L}}{\text{.atm/}}{{\text{K}}^{ - 1}}.mo{l^{ - 1}}) \times 307.9K}}$
Therefore,
$\dfrac{n}{V} = 0.0479{\text{mol}}{\text{.}}{{\text{L}}^{ - 1}}$
We have to know about the density in $mol.{L^{ - 1}}$. So that the above calculated value is multiplied by the molecular mass of $Cl$.
One mole of molar mass = $35.45g/mol$
Therefore, two moles of molar mass = $70.9g/mol$ .
Then,
$(70.9{\text{ g/mol) }} \times {\text{ (0}}{\text{.0479 mol/L) = 3}}{\text{.40 g/L}}$
Hence,
The density of chlorine gas = $3.40g/L$ .
Note: We have to know medications created with chlorine science are utilized to treat numerous ailments and illnesses, including elevated cholesterol, diabetes, malignancy, stomach ulcers, frailty, gloom, asthma, hypertension, irritation, and epilepsy. In different cases, chlorine science assumes a supporting part in drug combination.
Nowadays, chlorine is used for pools, elaborate lakes and aquaria, sewage and wastewater, and different sorts of water supplies. Chlorine gas likewise is utilized as a sanitizer, Microbiota or microbicide, an algicide in food preparing frameworks, mash, and paper factory frameworks, and business and mechanical water-cooling frameworks.
Complete step by step answer:
We have to know that the ideal gas behavior, then the ideal gas behavior formula has to be used.
Given details,
$P = 1.21{\text{atm}}$
The unit of the temperature is converted into celsius into kelvin,
$T = 34.9^\circ C = 307.9K$
By using the following formula,
$PV = nRT$
Then, we have to rewrite the above equation,
$\dfrac{n}{V} = \dfrac{P}{{RT}}$
Where,
$R = 0.0821{\text{ L}}{\text{.atm/}}{{\text{K}}^{ - 1}}mo{l^{ - 1}}$
Applying all the values in the above equation,
$\dfrac{n}{V} = \dfrac{{1.21{\text{ atm}}}}{{(0.0821{\text{ L}}{\text{.atm/}}{{\text{K}}^{ - 1}}.mo{l^{ - 1}}) \times 307.9K}}$
Therefore,
$\dfrac{n}{V} = 0.0479{\text{mol}}{\text{.}}{{\text{L}}^{ - 1}}$
We have to know about the density in $mol.{L^{ - 1}}$. So that the above calculated value is multiplied by the molecular mass of $Cl$.
One mole of molar mass = $35.45g/mol$
Therefore, two moles of molar mass = $70.9g/mol$ .
Then,
$(70.9{\text{ g/mol) }} \times {\text{ (0}}{\text{.0479 mol/L) = 3}}{\text{.40 g/L}}$
Hence,
The density of chlorine gas = $3.40g/L$ .
Note: We have to know medications created with chlorine science are utilized to treat numerous ailments and illnesses, including elevated cholesterol, diabetes, malignancy, stomach ulcers, frailty, gloom, asthma, hypertension, irritation, and epilepsy. In different cases, chlorine science assumes a supporting part in drug combination.
Nowadays, chlorine is used for pools, elaborate lakes and aquaria, sewage and wastewater, and different sorts of water supplies. Chlorine gas likewise is utilized as a sanitizer, Microbiota or microbicide, an algicide in food preparing frameworks, mash, and paper factory frameworks, and business and mechanical water-cooling frameworks.
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