
Density of \[3M\] of \[NaCl\] is\[1.25g/mL\] . Calculate the volume of water required to make \[1000{\text{ }}mL\] of this \[NaCl\] solution. [Consider the density of water as \[1g/mL\] ]
A. \[1074.5{\text{ }}mL\]
B. \[1250{\text{ }}mL\]
C. \[824.5{\text{ }}mL\]
D. \[1000{\text{ }}mL\]
Answer
564.9k+ views
Hint: Molarity and density are different ways of expressing essentially the same thing. Density is the mass of a solid, liquid or gas divided by its volume whereas molarity is the number of moles of solute per liter of solution. Density is not a term used for the concentration of any solution, whereas molarity is a concentration term.
Complete step by step answer:
According to the question,
Density (\[d\] ) of sodium chloride (\[NaCl\]) = \[1.25g/mL\]
Concentration of sodium chloride = \[3M\]= \[3{\text{ }}moles\] in one liter of the solution
Molar mass of sodium chloride $ = NaCl = 23 + 35.5 = 58.5g$
The volume of the solution is given as = $1L = 1000mL$
As we know that the density is defined as the mass per unit volume of any substance. So, mathematically it can be written as:
$d = \dfrac{m}{V}$
Thus, $m = d \times V$
Substituting the values for sodium chloride in the above equation, we have:
$m = 1.25g/mL \times 1000mL = 1250g$
The mass of sodium chloride solution is found to be = $m = 1250g$
We know that the mole of any substance is the ratio of the weight of the solute and the molar mass of the solute. Mathematically, this can be written as:
$n = \dfrac{w}{{{M_w}}}$
Thus, $w = n \times {M_w}$
Substituting the values, we have:
$m = 3 \times 58.5 = 175.5g$
Thus, the mass of the sodium chloride dissolved (solute) in the solvent is found to be = $w = 175.5g$ .
We know that, mass of solution = mass of solvent + mass of solute
Hence, the mass of the solvent = mass of solution – mass of solute
Mass of solvent = $(1250 - 175.5)g = 1074.5g$
Thus, the correct option is A. \[1074.5{\text{ }}mL\] .
Note:
Density is the amount of particles of the solute present in the solution when the particles dissolve in the solvent. Concentration is a specific term used for defining the strength of a solution and the various and most common concentration terms used in analytical chemistry include molarity, normality, molality, etc.
Complete step by step answer:
According to the question,
Density (\[d\] ) of sodium chloride (\[NaCl\]) = \[1.25g/mL\]
Concentration of sodium chloride = \[3M\]= \[3{\text{ }}moles\] in one liter of the solution
Molar mass of sodium chloride $ = NaCl = 23 + 35.5 = 58.5g$
The volume of the solution is given as = $1L = 1000mL$
As we know that the density is defined as the mass per unit volume of any substance. So, mathematically it can be written as:
$d = \dfrac{m}{V}$
Thus, $m = d \times V$
Substituting the values for sodium chloride in the above equation, we have:
$m = 1.25g/mL \times 1000mL = 1250g$
The mass of sodium chloride solution is found to be = $m = 1250g$
We know that the mole of any substance is the ratio of the weight of the solute and the molar mass of the solute. Mathematically, this can be written as:
$n = \dfrac{w}{{{M_w}}}$
Thus, $w = n \times {M_w}$
Substituting the values, we have:
$m = 3 \times 58.5 = 175.5g$
Thus, the mass of the sodium chloride dissolved (solute) in the solvent is found to be = $w = 175.5g$ .
We know that, mass of solution = mass of solvent + mass of solute
Hence, the mass of the solvent = mass of solution – mass of solute
Mass of solvent = $(1250 - 175.5)g = 1074.5g$
Thus, the correct option is A. \[1074.5{\text{ }}mL\] .
Note:
Density is the amount of particles of the solute present in the solution when the particles dissolve in the solvent. Concentration is a specific term used for defining the strength of a solution and the various and most common concentration terms used in analytical chemistry include molarity, normality, molality, etc.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

What is periodicity class 11 chemistry CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

Mention the basic forces in nature class 11 physics CBSE

