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Density of 3M of NaCl is1.25g/mL . Calculate the volume of water required to make 1000 mL of this NaCl solution. [Consider the density of water as 1g/mL ]
A. 1074.5 mL
B. 1250 mL
C. 824.5 mL
D. 1000 mL

Answer
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Hint: Molarity and density are different ways of expressing essentially the same thing. Density is the mass of a solid, liquid or gas divided by its volume whereas molarity is the number of moles of solute per liter of solution. Density is not a term used for the concentration of any solution, whereas molarity is a concentration term.

Complete step by step answer:
According to the question,
Density (d ) of sodium chloride (NaCl) = 1.25g/mL
Concentration of sodium chloride = 3M= 3 moles in one liter of the solution
Molar mass of sodium chloride =NaCl=23+35.5=58.5g
The volume of the solution is given as = 1L=1000mL
As we know that the density is defined as the mass per unit volume of any substance. So, mathematically it can be written as:
d=mV
Thus, m=d×V
Substituting the values for sodium chloride in the above equation, we have:
m=1.25g/mL×1000mL=1250g
The mass of sodium chloride solution is found to be = m=1250g
We know that the mole of any substance is the ratio of the weight of the solute and the molar mass of the solute. Mathematically, this can be written as:
n=wMw
Thus, w=n×Mw
Substituting the values, we have:
m=3×58.5=175.5g
Thus, the mass of the sodium chloride dissolved (solute) in the solvent is found to be = w=175.5g .
We know that, mass of solution = mass of solvent + mass of solute
Hence, the mass of the solvent = mass of solution – mass of solute
Mass of solvent = (1250175.5)g=1074.5g

Thus, the correct option is A. 1074.5 mL .

Note:
Density is the amount of particles of the solute present in the solution when the particles dissolve in the solvent. Concentration is a specific term used for defining the strength of a solution and the various and most common concentration terms used in analytical chemistry include molarity, normality, molality, etc.