
Decide whether y=2 is a root of the quadratic equation: ${y^2} - 4y + 2 = 0$
Answer
619.2k+ views
Hint: Here we will verify whether 2 is a zero of the quadratic equation of ${y^2} - 4y + 2 = 0$ i.e. by substituting the value of y as 2 then the value of the equation must be zero.
“Complete step-by-step answer:”
Given,
${y^2} - 4y + 2 = 0 \to (1)$
We have to check whether y=2 is its root or not.
As we know, the root of a quadratic equation means it will satisfy the quadratic equation.
So after putting y=2 in equation (1), we get
$ \Rightarrow 4 - 8 + 2 = - 2$
We can clearly see it’s not satisfying the equation, so y=2 is not the root of the equation.
Note: This type of quadratic equation is being checked by putting the value and nothing else.
“Complete step-by-step answer:”
Given,
${y^2} - 4y + 2 = 0 \to (1)$
We have to check whether y=2 is its root or not.
As we know, the root of a quadratic equation means it will satisfy the quadratic equation.
So after putting y=2 in equation (1), we get
$ \Rightarrow 4 - 8 + 2 = - 2$
We can clearly see it’s not satisfying the equation, so y=2 is not the root of the equation.
Note: This type of quadratic equation is being checked by putting the value and nothing else.
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