
Cyanogen ,${(CN)_2}$ ,has a _________shape structure.
A.Linear
B.Zig-Zag
C.Square
D.Cyclic
Answer
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Hint: There are three basic steps to determining the molecular shape of a molecule:
1.Write the Lewis dot structure of the molecule. That gives you the steric number\[(SN)\] — the number of bond pairs and lone pairs around the central atom.
2.Use the \[(SN)\] and VSEPR theory to determine the electron pair geometry of the molecule.
3.Use the VSEPR shape to determine the angles between the bonding pairs.
VSEPR principles: The repulsion between valence electron pairs in the outer shell of the central atom tells about the shape of the molecule. You must determine the steric number \[(SN)\] — the number of bonding pairs and lone pairs about the central atom.
Lone pairs repel more than bond bonding pairs.
Complete step by step answer:
In chemistry, the linear molecular geometry describes the geometry around a central atom bonded to two other atoms (or ligands) placed at a bond-angle of 180°.
Or we can say that If all electrons pairs are acting as bonding electrons, leaving no lone pair on the central atom $(A{X_2})$, then the molecule will be linear
In Cyanogen also there is no lone pair on central metal atom and there is a bond angle of 180°in the bonded atoms,hence it has a linear shape
So, the correct answer is Option A.
Note: When we apply VSEPR theory, we have to keep in mind that the electron pairs of the central atom, disregarding the difference between bonding pairs and lone pairs. These pairs are then allowed to move around the central atom and to take positions so that can maximize their mutual separations.
Cyanogen is the chemical compound with the formula ${(CN)_2}$ .Cyanogen molecules consist of two $CN$ groups – analogous to diatomic halogen molecules, such as \[C{l_2}\]The two cyano groups are bonded together at their carbon atoms: $N \equiv C - C \equiv N$
It Is also a pseudohalogen
1.Write the Lewis dot structure of the molecule. That gives you the steric number\[(SN)\] — the number of bond pairs and lone pairs around the central atom.
2.Use the \[(SN)\] and VSEPR theory to determine the electron pair geometry of the molecule.
3.Use the VSEPR shape to determine the angles between the bonding pairs.
VSEPR principles: The repulsion between valence electron pairs in the outer shell of the central atom tells about the shape of the molecule. You must determine the steric number \[(SN)\] — the number of bonding pairs and lone pairs about the central atom.
Lone pairs repel more than bond bonding pairs.
Complete step by step answer:
In chemistry, the linear molecular geometry describes the geometry around a central atom bonded to two other atoms (or ligands) placed at a bond-angle of 180°.
Or we can say that If all electrons pairs are acting as bonding electrons, leaving no lone pair on the central atom $(A{X_2})$, then the molecule will be linear
In Cyanogen also there is no lone pair on central metal atom and there is a bond angle of 180°in the bonded atoms,hence it has a linear shape
So, the correct answer is Option A.
Note: When we apply VSEPR theory, we have to keep in mind that the electron pairs of the central atom, disregarding the difference between bonding pairs and lone pairs. These pairs are then allowed to move around the central atom and to take positions so that can maximize their mutual separations.
Cyanogen is the chemical compound with the formula ${(CN)_2}$ .Cyanogen molecules consist of two $CN$ groups – analogous to diatomic halogen molecules, such as \[C{l_2}\]The two cyano groups are bonded together at their carbon atoms: $N \equiv C - C \equiv N$
It Is also a pseudohalogen
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