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How much Cu can be obtained from 100g of CuSO4 ?

Answer
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Hint: One mole of Copper Sulphate is generated from one mole of Cu2+ and a mole of SO42 ions. The molar mass of CuSO4 and Cu are 160 grams and 64 grams respectively.

Step-by-Step Solution:
Before moving onto the specifics of this question, let us first look at how the compound CuSO4 is made and the chemical reaction involved along with its equation.
- Copper sulphate is produced industrially by treating copper metal with hot concentrated sulfuric acid or its oxides with dilute sulfuric acid.
- It can be noted that the oxidation state exhibited by the copper atom in a CuSO4 molecule is +2.
The ionic reaction of the above reaction is given by:
Cu2++SO42CuSO4
Having now understood how CuSO4 is prepared, let us now move on to the specifics of this question.
Molecular mass of CuSO4 = Atomic mass of Cu + Atomic mass of S + 4(Atomic mass of O)
Molecular mass of CuSO4 = 64 + 32 + 4(16)
Molecular mass of CuSO4 = 160gmmol1
Mass of CuSO4 given= 100 g
Moles of CuSO4=Weight of CuSO4Molecular weight of CuSO4
Moles of CuSO4=100gm160gm
Moles of CuSO4=0.625mole

- We have already established above that one mole of CuSO4 contains one mole of Cu2+ and one mole of SO42 .
So, we can say that 0.625 mole of CuSO4 contains 0.625 moles of Cu2+ and 0.625 moles of SO42 .
Thus, Mass of Cu2+in 100 grams of CuSO4= Moles of copper × Atomic weight of Copper
Mass of Cu2+in 100 grams of CuSO4= 0.625×64
Mass of Cu2+in 100 grams of CuSO4= 40gm

Hence, by our calculations, we can safely conclude that 40 grams of Copper is obtained from 100 grams of CuSO4 solution.

Note: This solution is directly related to the law of constant proportions which states that a given chemical compound always contains its component elements in a fixed ratio and does not depend on its source and method of preparation.