What is the correct order of acidic strength of oxides of Nitrogen:
$(A){N_2}O > NO > {N_2}{O_3} > {N_2}{O_5}$
$(B){N_2}{O_3} > NO > {N_2}O > {N_2}{O_5}$
$(C){N_2}O > {N_2}{O_5} > {N_2}{O_3} > NO$
$(D){N_2}{O_5} > {N_2}{O_3} > NO > {N_2}O$
Answer
522k+ views
Hint: Nitrogen is present in the p-block of the modern periodic table. It is a highly electronegative element and hence, it is considered as a non-metal. It forms various oxides when it reacts with oxygen in different compositions. The oxides of nitrogen can be acidic, basic and neutral in nature depending on the oxidation state of nitrogen in that oxide.
Complete answer:
Nitrogen can form many oxides when it reacts with oxygen in different proportions such as:
Nitric oxide ( $NO$ )
Nitrous oxide ( ${N_2}O$ )
Dinitrogen trioxide ( ${N_2}{O_3}$ )
Nitrogen pentoxide ( ${N_2}{O_5}$ )
These nitrogen oxides can be acidic, basic and neutral in nature depending on the oxidation state of nitrogen in that oxide because as the oxidation state increases the acidic character of the oxide increases and vice versa.
So, now we will calculate the oxidation state of nitrogen in all these oxides given:
Nitric oxide ( $NO$ )
Let the oxidation state of nitrogen be x.
$x + ( - 2) = 0$
$x = + 2$
Nitrous oxide ( ${N_2}O$ )
Let the oxidation state of nitrogen be x.
$2x + ( - 2) = 0$
On solving, we get
$x = + 1$
Dinitrogen trioxide ( ${N_2}{O_3}$ )
Let the oxidation state of nitrogen be x.
$2x + 3( - 2) = 0$
On solving, we get
$x = + 3$
Nitrogen pentoxide ( ${N_2}{O_5}$ )
Let the oxidation state of nitrogen be x.
$2x + 5( - 2) = 0$
On solving, we get
$x = + 5$
So, as we know that greater the oxidation state of nitrogen, more will be its acidic strength.
Hence, the correct order of acidic strength of oxides of nitrogen is:
${N_2}{O_5} > {N_2}{O_3} > NO > {N_2}O$
So, the correct answer is “Option D”.
Note:
We know that nitrogen is present in the p-block of the modern periodic table and has high electronegativity. It is considered non-metal. Now, we know that non-metal oxides are acidic in nature. But some oxides of nitrogen are neutral in nature such as Nitric oxide ( $NO$ ) and Nitrous oxide ( ${N_2}O$ ).
Complete answer:
Nitrogen can form many oxides when it reacts with oxygen in different proportions such as:
Nitric oxide ( $NO$ )
Nitrous oxide ( ${N_2}O$ )
Dinitrogen trioxide ( ${N_2}{O_3}$ )
Nitrogen pentoxide ( ${N_2}{O_5}$ )
These nitrogen oxides can be acidic, basic and neutral in nature depending on the oxidation state of nitrogen in that oxide because as the oxidation state increases the acidic character of the oxide increases and vice versa.
So, now we will calculate the oxidation state of nitrogen in all these oxides given:
Nitric oxide ( $NO$ )
Let the oxidation state of nitrogen be x.
$x + ( - 2) = 0$
$x = + 2$
Nitrous oxide ( ${N_2}O$ )
Let the oxidation state of nitrogen be x.
$2x + ( - 2) = 0$
On solving, we get
$x = + 1$
Dinitrogen trioxide ( ${N_2}{O_3}$ )
Let the oxidation state of nitrogen be x.
$2x + 3( - 2) = 0$
On solving, we get
$x = + 3$
Nitrogen pentoxide ( ${N_2}{O_5}$ )
Let the oxidation state of nitrogen be x.
$2x + 5( - 2) = 0$
On solving, we get
$x = + 5$
So, as we know that greater the oxidation state of nitrogen, more will be its acidic strength.
Hence, the correct order of acidic strength of oxides of nitrogen is:
${N_2}{O_5} > {N_2}{O_3} > NO > {N_2}O$
So, the correct answer is “Option D”.
Note:
We know that nitrogen is present in the p-block of the modern periodic table and has high electronegativity. It is considered non-metal. Now, we know that non-metal oxides are acidic in nature. But some oxides of nitrogen are neutral in nature such as Nitric oxide ( $NO$ ) and Nitrous oxide ( ${N_2}O$ ).
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

