
Conversion of pyruvic acid into ethyl alcohol is mediated by
A) Phosphatase
B) Dehydrogenase
C) Decarboxylase and dehydrogenase
D) Catalase
Answer
565.8k+ views
Hint: Pyruvic acid is first transformed to acetaldehyde during the fermentation of alcohol. Acetaldehyde is then converted to ethyl alcohol.
Complete answer:
First we should know about fermentation to answer this question. Fermentation is a biochemical mechanism carried out by a wide variety of species that transforms sugar to acids, gases, or alcohol. As in the muscles of higher vertebrates, yeast and other microorganisms ferment glucose into ethanol and $CO_2$, instead of lactate. By glycolysis, glucose is transformed to pyruvate, and pyruvate is transformed to ethanol and $CO_2$ in a two-step process.
Now, let us find the solution from the options-
> Pyruvate is decarboxylated in the first step in an irreversible reaction that is catalysed by pyruvate decarboxylase. Pyruvate is converted to acetaldehyde in the presence of pyruvate decarboxylase. > Pyruvate decarboxylase needs $Mg^{2 +}$ and has a coenzyme, thiamine pyrophosphate, which is closely bound.
> In the second step, by the activity of alcohol dehydrogenase, acetaldehyde is reduced to ethanol, with the decreasing power given by NADH obtained from the dehydrogenation of glyceraldehyde 3-phosphate. Therefore, ethanol and $CO_2$ are the final components of ethanol fermentation.
From these we came to know that only option B is not correct and the options A and D are incorrect.
Thus, the correct answer is option C Decarboxylase and dehydrogenase.
Note: Two enzymes, carboxylase and carboxykinase, are needed to convert pyruvic acid back to phosphoenolpyruvate ( PEP). Pyruvic acid is either transformed to ethanol in alcohol fermentation or lactate in lactate fermentation under anaerobic conditions.
Complete answer:
First we should know about fermentation to answer this question. Fermentation is a biochemical mechanism carried out by a wide variety of species that transforms sugar to acids, gases, or alcohol. As in the muscles of higher vertebrates, yeast and other microorganisms ferment glucose into ethanol and $CO_2$, instead of lactate. By glycolysis, glucose is transformed to pyruvate, and pyruvate is transformed to ethanol and $CO_2$ in a two-step process.
Now, let us find the solution from the options-
> Pyruvate is decarboxylated in the first step in an irreversible reaction that is catalysed by pyruvate decarboxylase. Pyruvate is converted to acetaldehyde in the presence of pyruvate decarboxylase. > Pyruvate decarboxylase needs $Mg^{2 +}$ and has a coenzyme, thiamine pyrophosphate, which is closely bound.
> In the second step, by the activity of alcohol dehydrogenase, acetaldehyde is reduced to ethanol, with the decreasing power given by NADH obtained from the dehydrogenation of glyceraldehyde 3-phosphate. Therefore, ethanol and $CO_2$ are the final components of ethanol fermentation.
From these we came to know that only option B is not correct and the options A and D are incorrect.
Thus, the correct answer is option C Decarboxylase and dehydrogenase.
Note: Two enzymes, carboxylase and carboxykinase, are needed to convert pyruvic acid back to phosphoenolpyruvate ( PEP). Pyruvic acid is either transformed to ethanol in alcohol fermentation or lactate in lactate fermentation under anaerobic conditions.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

