
Construct $\Delta ABC$ in which $AB=4cm,BC=7cm,AC=3cm$. Which type of triangle is this?
Answer
610.8k+ views
Hint: To construct the triangle with given measurements, begin by drawing the longest side of the triangle using scale and pencil. Cut arcs of lengths equal to the two sides of the triangle from the endpoints of the side BC. Join the point of intersection of two arcs to the endpoints B and C of the line BC to construct the triangle with given dimensions.
Complete step-by-step answer:
We have to construct $\Delta ABC$ such that $AB=4cm,BC=7cm,AC=3cm$. To do so, we need a pencil, ruler, and compass.
We will begin by drawing the side $BC=7cm$ with the help of a pencil and scale.
As we have to draw $AB=4cm$, we will draw an arc of radius 4cm with B as the centre.
As we have to draw $AC=3cm$, we will draw an arc of radius 3cm with C as centre such that the two arcs intersect each other.
The point of intersection of the two arcs is labelled at A. We will now join point A with point B using a straight line.
Similarly, we will join point A with point C using a straight line.
We will now label the line segments AB and AC with their respective lengths.
Hence, we have constructed $\Delta ABC$ with the given measurements, as shown in the previous figure.
Note: One must keep in mind that all the lines should be straight and must be drawn with a pencil and scale. It’s necessary to label all the edges and vertices of the triangle during each step of construction. All the constructions must be clear and non – messy and should be drawn using a pencil only.
Complete step-by-step answer:
We have to construct $\Delta ABC$ such that $AB=4cm,BC=7cm,AC=3cm$. To do so, we need a pencil, ruler, and compass.
We will begin by drawing the side $BC=7cm$ with the help of a pencil and scale.
As we have to draw $AB=4cm$, we will draw an arc of radius 4cm with B as the centre.
As we have to draw $AC=3cm$, we will draw an arc of radius 3cm with C as centre such that the two arcs intersect each other.
The point of intersection of the two arcs is labelled at A. We will now join point A with point B using a straight line.
Similarly, we will join point A with point C using a straight line.
We will now label the line segments AB and AC with their respective lengths.
Hence, we have constructed $\Delta ABC$ with the given measurements, as shown in the previous figure.
Note: One must keep in mind that all the lines should be straight and must be drawn with a pencil and scale. It’s necessary to label all the edges and vertices of the triangle during each step of construction. All the constructions must be clear and non – messy and should be drawn using a pencil only.
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