Question

What is the compressibility factor of an ideal gas?
(A) $0$
(B) $1$
(C) $-1$
(D) $+2$

Answer 1

Hint: We know that ideal gas is hypothetical gas whose molecules occupy negligible space along with have no interaction as well as which consequently obey gaseous law exactly and the compressibility factor denoted by Z along known for compression factor of gas deviation factor.

Complete step-by-step answer:An ideal gas and we have to find its compressibility factor. Also the compressibility factor is defined in thermodynamics along with engineering frequently as where is pressure, where is density of gaseous and is specific gaseous constant and being molar mass which is absolute temperature in Kelvin or Rankine scale.
For an ideal gas compressibility factor is per definition. Also many real world applications required for the accuracy demand deviation from ideal gas behavior is real gas behavioral be taken in account. The value in general increases with pressure along with decrease with temperature. At high pressure molecules are colliding more often and thus this allows repulsive force between molecules to have noticeable effect making molar volume of real gas greater than molar volume of corresponding ideal gases which cause to exceed one. When pressures are lower molecules are free to move. In this case attractive force dominates making .The closer gas is to its critical point as well as it's boiling point and more deviates from ideal case.

Hence, the correct option is B i.e. the compressibility factor of an ideal gas $1$.

Note:Note that in deviation from ideal behavior it has become more and more significant that the much closer gas phase changes lower temperature. The following Compressibility factor value will be usually obtained with calculation from the EOS like viral equation.