Question

Complete the following reaction:
 \[Xe{F_4} + {H_2}O \to \]

Answer 1

Hint: A chemical reaction occurs when one or more compounds, known as reactants, are changed into one or more distinct substances, known as products. Chemical elements or compounds are examples of substances. The constituent atoms of the reactants are rearranged in a chemical reaction, resulting in the formation of various substances as products.
So, when we write chemical reactions we should balance RHS with LHS.

Complete answer:
As we have to complete this reaction:
\[Xe{F_4} + {H_2}O \to \]
As we know $Xe$ is Xenon, $F$ is fluorine, $H$ is hydrogen.
As this is an example of Disproportionation reactions
Disproportionation reactions: The reactions in which a single reactant is oxidized and reduced is known as Disproportionation reactions.
So, here $Xe$ will go to oxidation as well as reduction.
The reaction will as,
Hydrolysis of \[Xe{F_4}\] with water give \[Xe{O_3}\,and\,Xe\]
We will balance chemical reactions.
\[6Xe{F_4} + 12{H_2}O \to 4Xe + 2Xe{O_3} + 24HF + 3{O_2}\]

Note:
To balance a chemical reaction:
1: Identify the Reactants and Products: Identifying your reactants and products is the first step in balancing a chemical equation. Keep in mind that the reactants are on the left side of the equation. On the right, you'll see the items.
2: Calculate the total number of atoms: After that, you must figure out how many atoms of each element are on either side of the equation. This can be done by examining the subscripts or coefficients. You only have one atom of something if there is no subscript or coefficient present.
3: Incorporate Coefficients: I noted earlier that there are two techniques to figure out how many atoms of a specific element are present in a chemical equation: subscripts and coefficients. You modify coefficients when you balance a chemical equation. Subscripts are never changed. A whole number multiplier is referred to as a coefficient. These whole number multipliers (coefficients) are added to a chemical equation to ensure that the number of atoms on each side of the arrow is the same.