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Complete oxidation of 1 gm of glucose molecule gives rise to
(a) 68,60,000 cal
(b) 6,86,000 cal
(c) 68,600 cal
(d) 6,800 cal

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Last updated date: 24th Apr 2024
Total views: 393.6k
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Answer
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Hint: Glucose provides energy through oxidation. Energy processes include Glycolysis, TCA cycle, and Electron transport system.

Complete answer:
Complete oxidation of 1 gram of glucose molecule yields 686 kcal, which is equivalent to 686000 calories of energy.
- Cellular respiration is a combination of anabolic and catabolic reactions ( i.e; metabolism) and processes that take place in the cells of organisms to convert chemical energy from oxygen molecules or nutrients in the form of adenosine triphosphate (ATP) , and then release waste products.
- The reactions involved in respiration are catabolic reactions, which break larger molecules to smaller units, releasing energy, in particular in molecular oxygen, are replaced by stronger bonds in the products.
- Respiration is one of the key ways a cell releases the chemical energy
- The overall reactions are a combination of biochemical reactions, where some of them are redox reactions.
- Cellular respiration is a type of combustion reaction that does not resemble one when it occurs in a living cell.
- Amino acids, fats, and sugars are the nutrients that are commonly used by animal and plant cells in respiration.
- The most common oxidizing agent providing most of the chemical energy in this is the molecular oxygen (O2) and in the end, energy is stored in the form of ATP.
 So, the correct answer is ‘6,86,000 cal’.

Note: From an atom of glucose, two atoms of pyruvic acid are released in total. Therefore 36 ATPs are generated. During the process of Glycolysis 2 ATPs are formed. Therefore during the complete oxidation of glucose, the net ATP yielded is 38. This process is known as aerobic respiration.