
What is the colour of barium sulphate precipitate in the reaction of barium chloride and sodium sulphate?
Answer
492k+ views
Hint: Barium sulphate is an ionic compound consisting of barium and sulphate ions. Barium is an alkaline earth metal with a valency. Coloured salts are mainly formed by the transition metal ions that can show variable oxidation states and their electrons show d-d transition.
Complete answer:
The reaction between barium chloride and sodium sulphate is an example of a double displacement reaction where the anions and cations get interchanged giving rise to two new salts. The barium ion gets attracted to sulphate ions leaving behind chloride ions that form bonds with the free sodium ions. The reaction can be written as follows:
\[BaC{l_2}(aq) + N{a_2}S{O_4}(aq) \to BaS{O_4}(s) \downarrow + NaCl(aq)\]
The sodium chloride formed in the product is highly soluble and remains dissolved in the solution while the barium sulphate precipitates out as a white solid.
The precipitation observed in the case of barium sulphate is a consequence of its low solubility. Both the barium as well as sulphate ions are large in size and therefore less soluble in water.
The precipitate of barium sulphate is white in colour as the salt does not release any free electrons that undergo transitions in the visible energy range.
Note:
Solubility is determined by both lattice energy as well as hydration enthalpy. Smaller ions tend to have hydration enthalpy that excess lattice energy making the ionic solids more soluble. The presence of both the large sized ions in barium sulphate leads to a higher lattice energy than the hydration enthalpy making the salt less soluble and easy to precipitate.
Complete answer:
The reaction between barium chloride and sodium sulphate is an example of a double displacement reaction where the anions and cations get interchanged giving rise to two new salts. The barium ion gets attracted to sulphate ions leaving behind chloride ions that form bonds with the free sodium ions. The reaction can be written as follows:
\[BaC{l_2}(aq) + N{a_2}S{O_4}(aq) \to BaS{O_4}(s) \downarrow + NaCl(aq)\]
The sodium chloride formed in the product is highly soluble and remains dissolved in the solution while the barium sulphate precipitates out as a white solid.
The precipitation observed in the case of barium sulphate is a consequence of its low solubility. Both the barium as well as sulphate ions are large in size and therefore less soluble in water.
The precipitate of barium sulphate is white in colour as the salt does not release any free electrons that undergo transitions in the visible energy range.
Note:
Solubility is determined by both lattice energy as well as hydration enthalpy. Smaller ions tend to have hydration enthalpy that excess lattice energy making the ionic solids more soluble. The presence of both the large sized ions in barium sulphate leads to a higher lattice energy than the hydration enthalpy making the salt less soluble and easy to precipitate.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

