Question

Carbon dioxide acceptor in ${C_3}$ plants is
A. PEP
B. RuBP
C. PGA
D. NADP

Answer 1

Hint: In \[{C_3}\] plants the stable product formed is $3 - Carbon$ compound hence it is called as ${C_3}$ plants of Calvin cycle. The ${C_3}$ cycle is the dark reaction of photosynthesis because the photosynthesis in these plants doesn’t occur in the presence of light.

Complete answer:
PEP: phosphoenolpyruvate is a high energy compound hence it is also referred to as the second source of ATP. It is seen in the chloroplast it is the primary acceptor of $C{O_2}$ in ${C_4}$ cycle not in ${C_3}$.
Hence, option A is not correct
RuBP: $Ribulose - 1,5\,bisphosphate$ plays a major role in photosynthesis. In ${C_3}$ cycle during the chemical reaction of respiration ribulose accepts the $C{O_2}$ and releases the product $3 – Phosphoglycerate$.
PGA: phosphoglyceric acid is a $3 - Carbon$ compound sugar molecule acts as an intermediate in the ${C_3}$ cycle. It is released as a product after carbon dioxide is accepted by the RuBPhence, carbon dioxide molecules react with one molecule of RuBP to release two molecules of phosphoglyceric acid.
So, option C is not correct
NADP: nicotinamide adenine dinucleotide is an electron carrier its acts as a coenzyme for building complex molecules from the single-molecule as it is a carrier it cannot accept the carbon dioxide
So, option D is not correct
So, the correct answer is “Option B”.

Note:
$Ribulose - 1,5\,bisphosphate$ in C3 plants is seen in the mesophyll cells. It helps in the fixation of carbon dioxide from the atmosphere to give photosynthetic products. The ${C_3}$ cycle may not occur in the presence of light but it indirectly depends on the light-dependent products. The examples of ${C_3}$ plants are oats, rice, cotton, eucalyptus which are highly nutrient.