Question

How many carbon atoms of mass 12.00 a.m.u are in 12.00 g of C?

Answer 1

Hint: To solve this question, you should know what the terms like mole, Avagadro’s number or Avagadro’s constant means. You should also know that the mole is the amount of any substance equal to the Avagadro’s number. The Avagadro’s number is $6.022 \times {10^{23}}$number of entities.

Complete step by step answer:
The number of units present in one mole of any substance is known as th Avagadro’s number of Avagadro’s constant. The Avagadro’s number is equal to $6.022 \times {10^{23}}$. The unit can be electrons, ions, atoms or molecules which are dependent on the reaction and the nature of the substance.
In other words one mole of any substance is equal to $6.022 \times {10^{23}}$number of atoms, molecules or ions.
The Avogadro constant is the proportionality constant which gives a relation between the number of constituents like molecule, atoms or ions present in sample with the amount of sample present in the sample. The Avagadro’s constant is denoted by ${N_A}$.
The mole is defined as the amount of substance present in the system which contains elementary entities like atoms, molecule r ions present in 12 gram or 0.012 kilogram of carbon-12. The mole is represented by the symbol mol.

So, $6.022 \times {10^{23}}$of carbon atoms of mass 12.00 a.m.u are in 12.00 g of C

Note: The atomic weight of the carbon atom in the periodic table is given as 12.011 g which is the average mass of the isotopes of the carbon atom. It is calculated by adding the masses of the isotopes each multiplied by the natural abundance.