
Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.
Answer
548.4k+ views
Hint: We need to calculate the potential of hydrogen electrode in contact with a solution whose pH is 10. This question is of chapter electrochemistry.
Formula used: $ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{n}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}} $
Here $ n $ is the number of electrons
$ P $ stands for product
$ R $ stands for reactant.
Complete step by step answer
We already know that,
Given pH=10
We already that $ pH = - \log \left[ {{H^ + }} \right] $
$ \left[ {{H^ + }} \right] = {10^{ - 10}}M $
Also, for hydrogen electrode:
$ E = 0 $
$ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{1}\log \dfrac{{\left[ {{H_2}} \right]}}{{\left[ {{H^ + }} \right]}} $
Substituting the values:
$ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{1}\log \dfrac{1}{{{{10}^{ - 10}}}} = - 0.591{\text{V}} $
So, the potential of hydrogen electrode in contact with a solution whose pH is 10 is $ - 0.591{\text{V}} $ .
Note
In electrochemistry, the Nernst equation is an equation that relates the reduction potential of an electrochemical reaction (half-cell or full cell reaction) to the standard electrode potential, temperature, and activities (often approximated by concentrations) of the chemical species undergoing reduction and oxidation. Even under non-standard conditions, the cell potentials of electrochemical cells can be determined with the help of the Nernst equation. The Nernst equation is often used to calculate the cell potential of an electrochemical cell at any given temperature, pressure, and reactant concentration.
The Nernst equation is an important relation which is used to determine reaction equilibrium constants and concentration potentials as well as to calculate the minimum energy required in electrodialysis. It defines the relationship between cell potential to standard potential and to the activities of the electrically active species. It relates the effective concentrations of the components of a cell reaction to the standard cell potential.
To write the cell reaction corresponding to a cell diagram, the right-hand half reaction is written as a reduction, and the left-hand half-reaction, written as an oxidation.
Formula used: $ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{n}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}} $
Here $ n $ is the number of electrons
$ P $ stands for product
$ R $ stands for reactant.
Complete step by step answer
We already know that,
Given pH=10
We already that $ pH = - \log \left[ {{H^ + }} \right] $
$ \left[ {{H^ + }} \right] = {10^{ - 10}}M $
Also, for hydrogen electrode:
$ E = 0 $
$ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{1}\log \dfrac{{\left[ {{H_2}} \right]}}{{\left[ {{H^ + }} \right]}} $
Substituting the values:
$ {E_{cell}} = {E^0} - \dfrac{{0.0591}}{1}\log \dfrac{1}{{{{10}^{ - 10}}}} = - 0.591{\text{V}} $
So, the potential of hydrogen electrode in contact with a solution whose pH is 10 is $ - 0.591{\text{V}} $ .
Note
In electrochemistry, the Nernst equation is an equation that relates the reduction potential of an electrochemical reaction (half-cell or full cell reaction) to the standard electrode potential, temperature, and activities (often approximated by concentrations) of the chemical species undergoing reduction and oxidation. Even under non-standard conditions, the cell potentials of electrochemical cells can be determined with the help of the Nernst equation. The Nernst equation is often used to calculate the cell potential of an electrochemical cell at any given temperature, pressure, and reactant concentration.
The Nernst equation is an important relation which is used to determine reaction equilibrium constants and concentration potentials as well as to calculate the minimum energy required in electrodialysis. It defines the relationship between cell potential to standard potential and to the activities of the electrically active species. It relates the effective concentrations of the components of a cell reaction to the standard cell potential.
To write the cell reaction corresponding to a cell diagram, the right-hand half reaction is written as a reduction, and the left-hand half-reaction, written as an oxidation.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

