
How do you calculate the number of ions in a solution?
Answer
488.1k+ views
3 likes
Hint: To calculate the number of ions first we have to calculate the number of moles of the given element as the number of moles is already given, then number of ions can be calculate by using the relation between number of moles and Avogadro’s number. A mole is generally used as a unit for the number of atoms or molecules or particles of a material.
Complete step by step answer: The mole is a measurement or it is the basic unit which helps to calculate the amount of substance present in the given sample. 1 mole of a number is equal to Avogadro’s constant .
Number of mol is calculated by ratio of given mass to the molar mass.
Number of mol of sodium =
After calculating the number of moles, the number of ions will be equal to the product of the number of moles and Avogadro’s number.
number of ions=
where = Avogadro’s number.
So the correct answer is “a”:
Additional Information:
Note: 1 mole = particle or atoms or molecules or electrons or protons etc. The number of the constituent particles of atoms such as molecules or atoms or ions present in a given sample is related with the mass of the substance present in the sample using Avogadro's number. The SI unit of Avogadro’s number is inverse of mole i.e.
- Avogadro’s number is dimensionless. It also helps to relate the molar volume of a substance to the average volume which is occupied by one of the particles.
Complete step by step answer: The mole is a measurement or it is the basic unit which helps to calculate the amount of substance present in the given sample. 1 mole of a number is equal to Avogadro’s constant
Number of mol is calculated by ratio of given mass to the molar mass.
Number of mol of sodium =
After calculating the number of moles, the number of ions will be equal to the product of the number of moles and Avogadro’s number.
number of ions=
where
So the correct answer is “a”:
Additional Information:
Note: 1 mole =
- Avogadro’s number is dimensionless. It also helps to relate the molar volume of a substance to the average volume which is occupied by one of the particles.
Latest Vedantu courses for you
Grade 9 | CBSE | SCHOOL | English
Vedantu 9 CBSE Pro Course - (2025-26)
School Full course for CBSE students
₹37,300 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
The flightless birds Rhea Kiwi and Emu respectively class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
