Calculate the mean with the step deviation method from the following data.
Marks 0-10 10-20 20-30 30-40 40-50 No. of student 4 6 10 20 10
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No. of student | 4 | 6 | 10 | 20 | 10 |
Answer
583.8k+ views
Hint: Here, in this question, we will solve it by using the step deviation method. So the mid values will be calculated by taking out the average of the class interval. And the number of students will become frequent. So by taking the $\sum {{f_i}{u_1}} $ and by using the formula, we will get the mean.
Formula used:
Formula for solving the mean is given by,
$ \Rightarrow Mean(\bar x) = A + h\left[ {\dfrac{1}{N}\sum {{f_i}{u_1}} } \right]$
Here, $A$ , will be the mid-term of the mid values
$N$ , will be the total number of frequencies.
$\sum {{f_i}{u_1}} $ , will be the sum
Complete step-by-step answer:
So with the values given we will find out the required blacks. Therefore,
${d_i} = {x_i} - A$ and similarly ${u_i} = \dfrac{{{d_i}}}{h}$ . So with the table, we had calculated all those values. And the table will be represented as
N=50,
Total=26
So here after calculating all those values, we have
$h = 10,A = 25,N = 50,\sum {{f_i}{u_1}} = 26$ . So on substituting this all values in the formula and the formula is given by,
$ \Rightarrow Mean(\bar x) = A + h\left[ {\dfrac{1}{N}\sum {{f_i}{u_1}} } \right]$
So on substituting the values, we get the equation as
$ \Rightarrow Mean(\bar x) = 25 + 10\left[ {\dfrac{1}{{50}}\sum {26} } \right]$
Son solving the braces first we will get number as
$ \Rightarrow 30.2$
Hence, the mean will be equal to $30.2$ .
Note: So the basic step of deviation use is to find the mean as in this we get easily available. We can say that mean, median and mode are the three essential parts through which we can see the different perspectives of the same data. Median, which is being used for finding the middle number. Whereas mode is being used when any number is used on a frequent basis. So these are the basic ideas about the mean, median and mode.
Formula used:
Formula for solving the mean is given by,
$ \Rightarrow Mean(\bar x) = A + h\left[ {\dfrac{1}{N}\sum {{f_i}{u_1}} } \right]$
Here, $A$ , will be the mid-term of the mid values
$N$ , will be the total number of frequencies.
$\sum {{f_i}{u_1}} $ , will be the sum
Complete step-by-step answer:
So with the values given we will find out the required blacks. Therefore,
${d_i} = {x_i} - A$ and similarly ${u_i} = \dfrac{{{d_i}}}{h}$ . So with the table, we had calculated all those values. And the table will be represented as
| Class Interval | Mid value $x_i$ | Frequency $f_i$ | $d_i$ | $u_i$ | $u_i$$f_i$ |
| 0-10 | 5 | 4 | -20 | -2 | -8 |
| 10-20 | 15 | 6 | -10 | -1 | -6 |
| 20-30 | 25=A | 10 | 0 | 0 | 0 |
| 30-40 | 35 | 20 | 10 | 1 | 10 |
| 40-50 | 45 | 10 | 20 | 2 | 10 |
N=50,
Total=26
So here after calculating all those values, we have
$h = 10,A = 25,N = 50,\sum {{f_i}{u_1}} = 26$ . So on substituting this all values in the formula and the formula is given by,
$ \Rightarrow Mean(\bar x) = A + h\left[ {\dfrac{1}{N}\sum {{f_i}{u_1}} } \right]$
So on substituting the values, we get the equation as
$ \Rightarrow Mean(\bar x) = 25 + 10\left[ {\dfrac{1}{{50}}\sum {26} } \right]$
Son solving the braces first we will get number as
$ \Rightarrow 30.2$
Hence, the mean will be equal to $30.2$ .
Note: So the basic step of deviation use is to find the mean as in this we get easily available. We can say that mean, median and mode are the three essential parts through which we can see the different perspectives of the same data. Median, which is being used for finding the middle number. Whereas mode is being used when any number is used on a frequent basis. So these are the basic ideas about the mean, median and mode.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
In cricket, what is the term for a bowler taking five wickets in an innings?

In cricket, how many legal balls are there in a standard over?

What is deficiency disease class 10 biology CBSE

Select the word that is correctly spelled a Twelveth class 10 english CBSE

Bharatiya Janata Party was founded in the year A 1979 class 10 social science CBSE

The uses of bleaching powder are A It is used bleaching class 10 chemistry CBSE

