
Calculate the effective nuclear charge experienced by the $4s$ electron in potassium atom($Z = 19$.
Answer
562.5k+ views
Hint: The effective nuclear charge is the true nuclear charge minus the screening constant. It is due to the valence electrons present in the atom. The effective nuclear charge will be according to the formula and consequently, the effective nuclear charge will be the difference between the true nuclear charge and the screening constant.
Complete step by step answer:
We know that the effective charge is the true nuclear charge minus the screening constant. It is due to the valence electrons present in the atom. We have been given the potassium atom with the atomic number nineteen.
The electronic configuration of potassium, K is as follows
$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}$
Here it is having four shells in it. Therefore the formula for the effective nuclear charge is as follows
${({Z_{eff}})_{4s}} = Z - \sigma $
Where ${Z_{eff}}$ is the effective nuclear charge
$\sigma $ is the screening constant
$\sigma = $ $0.85 \times $number of electrons in $(n - 1)$ the shell $ + 1.00$ $ \times $ total number of electrons in the inner shell
$ \Rightarrow 0.85 \times 8 + 1.00 \times 10$
$ \Rightarrow 16.80$
Hence, ${Z_{eff}} = Z - \sigma $
$ \Rightarrow 19 - 16.80$
$ \Rightarrow 2.20$
Where the number of electrons in $(n - 1)$ th shell is eight
Total number of electrons in the inner shell is ten
Hence the effective nuclear charge of the potassium is $2.20$
Note: Effective nuclear charge increases from left to right across the row of a periodic table. It shows a sudden decrease when we go from one end of one row to the beginning of the next row in the periodic table. Also, the change in effective nuclear charge going down a column of the periodic table is generally less than that going across a row of the periodic table.
The rule used in finding the screening constant is termed to be Slater’s rule.
Complete step by step answer:
We know that the effective charge is the true nuclear charge minus the screening constant. It is due to the valence electrons present in the atom. We have been given the potassium atom with the atomic number nineteen.
The electronic configuration of potassium, K is as follows
$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}$
Here it is having four shells in it. Therefore the formula for the effective nuclear charge is as follows
${({Z_{eff}})_{4s}} = Z - \sigma $
Where ${Z_{eff}}$ is the effective nuclear charge
$\sigma $ is the screening constant
$\sigma = $ $0.85 \times $number of electrons in $(n - 1)$ the shell $ + 1.00$ $ \times $ total number of electrons in the inner shell
$ \Rightarrow 0.85 \times 8 + 1.00 \times 10$
$ \Rightarrow 16.80$
Hence, ${Z_{eff}} = Z - \sigma $
$ \Rightarrow 19 - 16.80$
$ \Rightarrow 2.20$
Where the number of electrons in $(n - 1)$ th shell is eight
Total number of electrons in the inner shell is ten
Hence the effective nuclear charge of the potassium is $2.20$
Note: Effective nuclear charge increases from left to right across the row of a periodic table. It shows a sudden decrease when we go from one end of one row to the beginning of the next row in the periodic table. Also, the change in effective nuclear charge going down a column of the periodic table is generally less than that going across a row of the periodic table.
The rule used in finding the screening constant is termed to be Slater’s rule.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

