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Calculate number of valence electrons and non-valence electrons in 5.6 ml of SO2 gas.

Answer
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Hint: From electronic configuration of the elements we can calculate the total number of electrons present in them.
The electronic configuration of Sulphur is 1s22s22p63s23p4
The electronic configuration of Oxygen is 1s22s22p4

Complete Solution :
- In the question it is asked to calculate the number of valence electrons and non-valence electrons in 5.6 ml of SO2 gas.
- Before going to calculate the number of valence and non-valence electrons, we should calculate the numbers of molecules present in 5.6 ml of SO2 gas.
- Therefore the formula to calculate the number of molecules in 5.6 ml of SO2 gas is as follows.
Number of molecules = (number of moles) (Avogadro number)
=5.622400×6.023×1023=1.50575×1020molecules

- Means 5.6 ml of SO2 gas at STP contains 1.50575×1020molecules .
- Now coming to the concept of valence and non-valence electrons present in SO2.
-Total number of electrons in one SO2 molecule = 16 + 8 + 8 = 32.
- Number of valence electrons present in Sulphur = 6
- Number of valence electrons present in Oxygen = 6
- So, the total number of valence electrons in one SO2 molecule is = 6 + 6 + 6 = 18.
- So, the number of non-valence electrons in one SO2 molecule is = 32 - 18 = 14.
- Now we have to calculate the number of valence and non-valence electrons in 1.50575×1020molecules .

- The number of valence electrons in 1.50575×1020molecules of sulphur dioxide is
=1.50575×1020×18=27.1035×1020=2.71035×1021

- The number of non-valence electrons in 1.50575×1020molecules of sulphur dioxide is
=1.50575×1020×14=21.0805×1020=2.10805×1021

Note: We are not supposed to calculate the number of valence and non-valence electrons in one sulphur dioxide molecule, we are supposed to calculate the number of valence and non-valence electrons in 5.6 ml of sulphur dioxide.
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