
How do you calculate for the isothermal expansion of 1.5 mol of an ideal gas from 20.0 L to 22.5 L?
Answer
453.6k+ views
Hint: The measure of disorder or randomness in a system is known as entropy of the system. Properties of a thermodynamic system such as pressure, heat capacity, and temperature can be described using entropy. Its SI unit is J/mol.
Complete answer:
When we divide the amount of heat that is absorbed or released in an isothermal and reversible process by the absolute temperature, we get the value of entropy change.
Now, we know that an ideal gas is a gas in which
- the molecules either attract or repel each other
- the molecules do not occupy any space themselves.
So, when the volume of an ideal gas increases without any changes in temperature, it is known as the isothermal expansion of an ideal gas.
Heat change during the isothermal expansion of an ideal gas is given by
This equation can be re-written as
Also, we know that
So, by using these equations, we can say that the change in entropy when gas is expanded isothermally and increases in volumes is given by
Where is the change in entropy, n is the number of moles, R is the gas constant, is the volume of gas after expansion, and is the volume of gas before expansion.
It is given to us that
n = 1.5 moles,
= 20 L,
= 22.5 L,
And R = 6.314 J/mol K
So, by using the formula, we get
So, the change in entropy for the isothermal expansion of 1.5 mol of an ideal gas from 20.0 L to 22.5 L is 1.47 J/K.
Note:
It should be noted that when we add the entropy changes of the system and surroundings, we get the total entropy change. It is given by
When the total entropy change of a reaction is positive, it indicates that the process is spontaneous.
When the total entropy change of a reaction is negative, it indicates that the process is nonspontaneous.
When the total entropy change of a reaction is 0, it indicates that the process is at equilibrium.
Complete answer:
When we divide the amount of heat that is absorbed or released in an isothermal and reversible process by the absolute temperature, we get the value of entropy change.
Now, we know that an ideal gas is a gas in which
- the molecules either attract or repel each other
- the molecules do not occupy any space themselves.
So, when the volume of an ideal gas increases without any changes in temperature, it is known as the isothermal expansion of an ideal gas.
Heat change during the isothermal expansion of an ideal gas is given by
This equation can be re-written as
Also, we know that
So, by using these equations, we can say that the change in entropy when gas is expanded isothermally and increases in volumes is given by
Where
It is given to us that
n = 1.5 moles,
And R = 6.314 J/mol K
So, by using the formula, we get
So, the change in entropy
Note:
It should be noted that when we add the entropy changes of the system and surroundings, we get the total entropy change. It is given by
When the total entropy change of a reaction is positive, it indicates that the process is spontaneous.
When the total entropy change of a reaction is negative, it indicates that the process is nonspontaneous.
When the total entropy change of a reaction is 0, it indicates that the process is at equilibrium.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Explain why it is said like that Mock drill is use class 11 social science CBSE

The non protein part of an enzyme is a A Prosthetic class 11 biology CBSE

Which of the following blood vessels in the circulatory class 11 biology CBSE

What is a zygomorphic flower Give example class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

The deoxygenated blood from the hind limbs of the frog class 11 biology CBSE
