
Brine solution on electrolysis will give:
(A).NaOH
(B).${{O}_{2}}$
(C).$C{{l}_{2}}$
(D).${{H}_{2}}$
Answer
557.4k+ views
Hint:To solve this question, first we have to understand the meaning of brine solution. A brine solution is a solution of sodium chloride i.e. NaCl and water.
Complete answer:
The electrolysis of the brine solution i.e. the solution of sodium chloride and water is a large-scale process which is used in the manufacturing of chlorine form water. The two most important chemicals which are obtained during the process of electrolysis of brine solution are sodium hydroxide and hydrogen.
The chlorine and sodium hydroxide which are produced during the process must be separated before they react with each other and form another compound.
The chemical reaction which occurs at the negative cathode electrode:
\[2{{H}^{+}}(aq)+2{{e}^{-}}\to {{H}_{2}}(g)\]
Other equations for the reactions at negative terminal:
\[2{{H}_{2}}O+2{{e}^{-}}\to {{H}_{2}}(g)+2O{{H}^{-}}(aq)\]
The reactions which occurs at the positive terminal i.e. anode is mentioned below:
\[C{{l}_{2}}\to 2C{{l}^{-}}+2{{e}^{-}}\]
Other equations for the reactions at positive terminal:
\[N{{a}^{+}}+O{{H}^{-}}\to NaOH\]
Hence, the correct answer is option (A), option (C), and option (D) i.e. Brine solution on electrolysis will give NaOH, $C{{l}_{2}}$and ${{H}_{2}}$.
Note:
Electrolysis is where the ionic compounds are separated from the simple compounds. The process of electrolysis only works when the compound contains ions. This means that covalent compounds cannot be separated by using the process of electrolysis. The covalent compounds cannot behave as an electrolyte because they do not contain charged ions, they contain neutral atoms in it which are joined together by a covalent bond i.e. the bond which is formed by sharing of electrons.
Complete answer:
The electrolysis of the brine solution i.e. the solution of sodium chloride and water is a large-scale process which is used in the manufacturing of chlorine form water. The two most important chemicals which are obtained during the process of electrolysis of brine solution are sodium hydroxide and hydrogen.
The chlorine and sodium hydroxide which are produced during the process must be separated before they react with each other and form another compound.
The chemical reaction which occurs at the negative cathode electrode:
\[2{{H}^{+}}(aq)+2{{e}^{-}}\to {{H}_{2}}(g)\]
Other equations for the reactions at negative terminal:
\[2{{H}_{2}}O+2{{e}^{-}}\to {{H}_{2}}(g)+2O{{H}^{-}}(aq)\]
The reactions which occurs at the positive terminal i.e. anode is mentioned below:
\[C{{l}_{2}}\to 2C{{l}^{-}}+2{{e}^{-}}\]
Other equations for the reactions at positive terminal:
\[N{{a}^{+}}+O{{H}^{-}}\to NaOH\]
Hence, the correct answer is option (A), option (C), and option (D) i.e. Brine solution on electrolysis will give NaOH, $C{{l}_{2}}$and ${{H}_{2}}$.
Note:
Electrolysis is where the ionic compounds are separated from the simple compounds. The process of electrolysis only works when the compound contains ions. This means that covalent compounds cannot be separated by using the process of electrolysis. The covalent compounds cannot behave as an electrolyte because they do not contain charged ions, they contain neutral atoms in it which are joined together by a covalent bond i.e. the bond which is formed by sharing of electrons.
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