
Between two ends of a bookshelf in your study are displayed five of your favourite puzzle books. You wish to place them in all possible combinations. It takes a minute to list each combination. How much time would it take to list all combinations?
[a] One hour
[b] Two hours
[c] Three hours
[d] Four hours
Answer
574.2k+ views
Hint: Use fundamental principle of counting. According to fundamental principle of counting if a task A can be done in m ways and another task B can be done in n ways then the number of ways of doing both the tasks is mn and the number of ways of doing either of the tasks is m+n. Hence determine the total possible arrangements of the books and hence determine the total time taken to arrange the books in all possible ways.
Complete step by step answer:
Let us denote the five places for the five books as P1, P2, P3, P4 and P5.
Now P1 can be filled in 5 different ways (five possible books)
P2 can be filled in 4 different ways (four choices only as we have selected one book for P1)
P3 can be filled in 3 different ways (We are left with only three books)
P4 can be filled in 2 different ways (Only two choices left)
P5 can be filled in 1 way (The remaining book)
We know by fundamental principle of counting if a task A can be done in m ways and another task B can be done in n ways then the number of ways of doing both the tasks is mn and the number of ways of doing either of the tasks is m+n
Hence the number of possible arrangements of the books is $5\times 4\times 3\times 2\times 1=120$
Since it takes 1 min for shifting from one arrangement to other, the total time taken to form all possible permutations assuming no permutation is repeated is $\dfrac{120}{1}=120\min =2hrs$
Hence the total time taken is 2 hours
So, the correct answer is “Option B”.
Note: [1] Alternative solution:
We know that the number of possible arrangements of n different things taken n at a time is given by $n!$
Hence the number of possible arrangements of the five different books is $5!=120$ which is the same as obtained above.
Proceeding as the above solution, we get option [b] is correct.
Complete step by step answer:
Let us denote the five places for the five books as P1, P2, P3, P4 and P5.
Now P1 can be filled in 5 different ways (five possible books)
P2 can be filled in 4 different ways (four choices only as we have selected one book for P1)
P3 can be filled in 3 different ways (We are left with only three books)
P4 can be filled in 2 different ways (Only two choices left)
P5 can be filled in 1 way (The remaining book)
We know by fundamental principle of counting if a task A can be done in m ways and another task B can be done in n ways then the number of ways of doing both the tasks is mn and the number of ways of doing either of the tasks is m+n
Hence the number of possible arrangements of the books is $5\times 4\times 3\times 2\times 1=120$
Since it takes 1 min for shifting from one arrangement to other, the total time taken to form all possible permutations assuming no permutation is repeated is $\dfrac{120}{1}=120\min =2hrs$
Hence the total time taken is 2 hours
So, the correct answer is “Option B”.
Note: [1] Alternative solution:
We know that the number of possible arrangements of n different things taken n at a time is given by $n!$
Hence the number of possible arrangements of the five different books is $5!=120$ which is the same as obtained above.
Proceeding as the above solution, we get option [b] is correct.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

