Question

Benzene carbaldehyde when reacts with concentrated $NaOH$ solution gives the products A and B. The product A can be used as food preservative and the product B is an aromatic hydroxy compound where $OH$ group is linked to $s{{p}^{3}}$hybridized carbon atom next to benzene ring. The products A and B respectively are:
(A)Sodium benzoate and phenol
(B)Sodium benzoate and phenyl methanol
(C)Sodium benzoate and cresol
(D)Sodium benzoate and picric acid

Answer 1

Hint: Benzene carbaldehyde whose formula is ( ${{C}_{6}}{{H}_{5}}.CHO$) and also called as benzaldehyde. In an organic compound aromatic hydroxy compounds referred to the compounds having an unsaturated ring containing alternating double and single bonds.

Complete answer:
The Cannizzaro reaction, named after its discoverer Stanislao Cannizzaro, is a chemical reaction involving the base-induced disproportionation of two non-enolizable aldehyde molecules to give a primary alcohol and a carboxylic acid.
In the given question when Benzene carbaldehyde is reacted with concentrated $NaOH$ solution, it undergoes Cannizzaro reaction where one of the product molecules is oxidised to carboxylate ion and another molecule is reduced to alcohol. The products A and B are sodium benzoate and phenyl methanol respectively. Here the product A can be used as food preservative and the product B is an aromatic hydroxy compound where $OH$ group is linked to $s{{p}^{3}}$ hybridised carbon atom next to benzene ring.

Hence, the option (B) is the correct answer.















Note: Cannizzaro reaction is given by aldehydes that do not have a α hydrogen atom. Acetaldehyde ($C{{H}_{3}}CHO$) has 3 α hydrogen atoms and thus does not undergo Cannizzaro reaction. Also, the reaction involves the base-induced disproportionation of two non-enolizable aldehyde molecules to give a primary alcohol and a carboxylic acid. The reaction starts with an assault on the carbonyl carbon by hydroxide, followed by deprotonation to give a dianion.