Answer
Verified
376.2k+ views
Hint: We know that precipitate is an insoluble solid. It comes from a liquid solution. When an insoluble solid comes out from a liquid solution, it is called precipitation. It can be seen as a suspension also. 2 soluble salts, when mixed, give an insoluble salt. This is precipitation.
Complete step by step answer:
We mentioned above that when two soluble salts are mixed, an insoluble solid would be formed.
When we look at the solubility rules, we can understand that most of the sulphates salts are soluble except barium, calcium and lead.
Similarly, most of the chloride salts are soluble except that of lead, silver and mercury.
In this question, barium chloride is added to E. We know that barium chloride is a soluble salt.
It is mentioned that when ${{BaC}}{{{l}}_{{2}}}$ and E reacts, an insoluble white precipitate is formed. We can say that E should also be soluble to give out precipitate which is an insoluble solid.
As mentioned above the product formed will be a salt of barium and in the salts of barium, sulphate salts are insoluble. Thus, the product can be barium sulphate.
${{BaC}}{{{l}}_{{2}}}$ is a neutral salt which in aqueous solution behaves as a simple salt.
Solution of ${{BaC}}{{{l}}_{{2}}}$ reacts with sulphate ion to produce a thick white precipitate of barium sulphate.
${{B}}{{{a}}^{{{2 + }}}}{{ + S}}{{{O}}_{{4}}}^{{{2 - }}}{{ }} \to {{ BaS}}{{{O}}_{{4}}}$ , where barium sulphate is thick white precipitate which is insoluble in dilute HCl
Therefore, E should be any soluble salts of sulphate. It can be both sodium or potassium sulphates.
${{BaC}}{{{l}}_{{2}}}{{(aq) + N}}{{{a}}_{{2}}}{{S}}{{{O}}_{{4}}}{{(aq)}} \to {{BaS}}{{{O}}_{{4}}}{{(s) + NaCl(aq)}}$ is an example of a precipitation reaction. It is a double displacement reaction. Since barium sulphate is insoluble in water, it precipitates.
We know that sulphate ions are insoluble in HCl since they are weak bases.
Thus, the anion present in sulphate ion ( ${{S}}{{{O}}_{{4}}}^{{{2 - }}}$)
Note:
Another reason for precipitate formation is due to the lowering of temperature. When the temperature is lowered, the solubility decreases and as a result precipitation occurs. This type of reaction can be used to detect sulphate ions. Precipitation reaction can be used to detect the presence of a particular ion in a solution. Thus, by knowing the solubility of some salts, we can prepare salt from another salt.
Complete step by step answer:
We mentioned above that when two soluble salts are mixed, an insoluble solid would be formed.
When we look at the solubility rules, we can understand that most of the sulphates salts are soluble except barium, calcium and lead.
Similarly, most of the chloride salts are soluble except that of lead, silver and mercury.
In this question, barium chloride is added to E. We know that barium chloride is a soluble salt.
It is mentioned that when ${{BaC}}{{{l}}_{{2}}}$ and E reacts, an insoluble white precipitate is formed. We can say that E should also be soluble to give out precipitate which is an insoluble solid.
As mentioned above the product formed will be a salt of barium and in the salts of barium, sulphate salts are insoluble. Thus, the product can be barium sulphate.
${{BaC}}{{{l}}_{{2}}}$ is a neutral salt which in aqueous solution behaves as a simple salt.
Solution of ${{BaC}}{{{l}}_{{2}}}$ reacts with sulphate ion to produce a thick white precipitate of barium sulphate.
${{B}}{{{a}}^{{{2 + }}}}{{ + S}}{{{O}}_{{4}}}^{{{2 - }}}{{ }} \to {{ BaS}}{{{O}}_{{4}}}$ , where barium sulphate is thick white precipitate which is insoluble in dilute HCl
Therefore, E should be any soluble salts of sulphate. It can be both sodium or potassium sulphates.
${{BaC}}{{{l}}_{{2}}}{{(aq) + N}}{{{a}}_{{2}}}{{S}}{{{O}}_{{4}}}{{(aq)}} \to {{BaS}}{{{O}}_{{4}}}{{(s) + NaCl(aq)}}$ is an example of a precipitation reaction. It is a double displacement reaction. Since barium sulphate is insoluble in water, it precipitates.
We know that sulphate ions are insoluble in HCl since they are weak bases.
Thus, the anion present in sulphate ion ( ${{S}}{{{O}}_{{4}}}^{{{2 - }}}$)
Note:
Another reason for precipitate formation is due to the lowering of temperature. When the temperature is lowered, the solubility decreases and as a result precipitation occurs. This type of reaction can be used to detect sulphate ions. Precipitation reaction can be used to detect the presence of a particular ion in a solution. Thus, by knowing the solubility of some salts, we can prepare salt from another salt.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Draw a diagram showing the external features of fish class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Select the word that is correctly spelled a Twelveth class 10 english CBSE
How fast is 60 miles per hour in kilometres per ho class 10 maths CBSE