Question

Assuming fully decomposed, the volume of $C{{O}_{2}}$ released at STP on heating 9.85 g of $BaC{{O}_{3}}$will be : (Atomic mass of Ba= 137).
A.0.84 L
B.2.24 L
C.4.06 L
D.1.12 L

Answer 1

Hint: Before answering the question, we should know about Barium carbonate. Barium carbonate has a formula $BaC{{O}_{3}}$ is an inorganic compound. . It is white in color and insoluble in water or partially soluble. It is an alkali carbonate. It is found as a mineral in the environment by the name witherite.

Complete answer:
Barium carbonate is considered an important barium compound in a commercial sense.
Preparation of Barium carbonate :
It is formed with the help of the soda ash method by the treatment of barium sulfide with sodium carbonate at 60-70$^{\circ }C$or by carbon dioxide at 40-90$^{\circ }C$.
The reaction of the soda ash process is :
$BaS+{{H}_{2}}O+C{{O}_{2}}\to BaC{{O}_{3}}+{{H}_{2}}S$
$BaC{{O}_{3}}$ liberates $C{{O}_{2}}$ on decomposition as
$BaC{{O}_{{{3}_{\,197g}}}}\to BaO+C{{O}_{{{2}_{\,22.4L\,at\,STP}}}}\uparrow $
197 g of $BaC{{O}_{3}}$gives 22.4 L of$C{{O}_{2}}$at STP
Therefore, 9.85 g of $BaC{{O}_{3}}$will give $C{{O}_{2}}$= $\dfrac{22.4\times 9.85}{197}$= 1.12 L

So, Option (A) 1.12 L is correct.

Additional information:
STP refers to the abbreviation for Standard temperature and Pressure in chemistry. When we do calculations on gases like gas density. 273 K/ 0$^{\circ }C$/ 32$^{\circ }F$is the standard temperature and 1 atm pressure is the standard pressure. It is the freezing point of pure water at sea level atmospheric pressure. One mole of gas occupies 22.4 L of molar volume at STP.

Note:
Uses of STP are: To express the fluid flow rate and the volumes of liquids and gases, STP is important. The gases and liquids are dependent on pressure and temperature. It can only be applied if standard state conditions are applied in the question. The conditions like standard pressure and temperature. It could be acknowledged by the superscript circle.