Question

Assertion: NaCl is a basic salt
Reason: Hydrolysis of NaCl reveals the formation of NaOH and HCl
(A)- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
(B)- Both Assertion and Reason are correct but Reason is not correct explanation for Assertion
(C)- Assertion is incorrect but Reason is correct
(D)- Both Assertion and Reason are incorrect

Answer 1

Hint: The nature of solution depends on the reactivity of the ions (that is, the conjugate base and conjugate acid) whether it produces either ${{H}^{+}}\,or\,O{{H}^{-}}$ ions with water on hydrolysis.

Complete step by step answer:
The NaCl salt formed by the neutralization reaction of sodium hydroxide and hydrochloric acid give sodium chloride and water. This a strong acid (HCl) and strong base (NaOH) salt.
\[HCl+NaOH\to NaCl+{{H}_{2}}O\]
The hydrochloric acid and potassium hydroxide is a strong acid and base respectively, because on dissolving in water, they dissociate completely and ionize in the solution, giving proton or hydroxide ion respectively as follows:
\[HCl\to {{H}^{+}}+Cl\]
\[NaOH\to N{{a}^{+}}+O{{H}^{-}}\]

Where, the $C{{l}^{-}}$ is the conjugate base of strong acid, HCl and $N{{a}^{+}}$ is the conjugate acid of strong base, NaOH.
In the hydrolysis process, the strong acid and strong base salt dissociates into its constituent ions along with water. But, if this conjugate acid, $N{{a}^{+}}$ again gains the hydroxide ion giving back NaOH or in the case of conjugate base, $C{{l}^{-}}$ which gains a proton forming back the HCl. This way it again produces either ${{H}^{+}}\,or\,O{{H}^{-}}$ into solution.
Thus, in this manner there is no change in the concentration of the proton and hydroxide ion in the solution. So, the solution remains neutral as the ions do not react back with ${{H}^{+}}\,or\,O{{H}^{-}}$ ions of water. With no effect in the acidity of the NaCl solution, the pH $\approx $ 7.
So, we have the NaCl as a neutral salt of a strong acid and base, thereby, making the assertion incorrect.
Whereas, the hydrolysis which is reverse of neutralization reaction does show the presence of NaOH and HCl, thereby making the reason correct.

So, the correct answer is “Option C”.

Note: The NaCl is neutral in nature like water with the $\left[ {{H}^{+}} \right]=\left[ O{{H}^{-}} \right]$ in the solution. Out of the cation or anions of a salt, one acting as a spectator ion while the other ion reacts with ions in water. It does change this concentration of proton or hydroxide ion, thereby the acidic nature.