What is the area of the plot shown in the figure?
A) $\dfrac{1}{2}\left( {az + by + ct + dx} \right)$
B) $\dfrac{1}{2}\left( {bt + cx + ay + az} \right)$
C) $\dfrac{1}{2}\left( {cx + bt + by + az} \right)$
D) $\dfrac{1}{2}\left( {d + t} \right)\left( {c + x} \right) + \dfrac{1}{2}\left( {a + b} \right)\left( {y + z} \right)$
Answer
591.9k+ views
Hint: The given figure consists of four triangles. The formula to find the area of the triangle when its base and height is given is: $\dfrac{1}{2}bh$ where $b$ stands for base and $h$ stands for height.
Complete step-by-step solution:
The total area of figure $ABCDEF$ is given as the sum of the area of the $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$,that is given as:
$Ar\left( {ABCDEF} \right) = Ar\left( {\Delta ABC} \right) + Ar\left( {\Delta BCD} \right) + Ar\left( {\Delta BED} \right) + Ar\left( {\Delta EFD} \right)$ ……(i)
In triangle $\Delta ABC$,
Base of the triangle is $a$.
Height of the triangle is $z$.
Hence, area of the triangle is given by,
$
\Delta ABC = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times z……(ii)
$
In triangle $\Delta BCD$,
Base of the triangle is $a$.
Height of the triangle is $y$.
Hence, area of the triangle is given by,
$
\Delta BCD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times y……(iii)
$
In triangle $\Delta BED$,
Base of the triangle is$b$ .
Height of the triangle is$t$.
Hence, area of the triangle is given by,
$
\Delta BED = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times b \times t……(iv)
$
In triangle $\Delta EFD$,
Base of the triangle is $c$.
Height of the triangle is $x$.
Hence, area of the triangle is given by,
$
\Delta EFD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times c \times x ……(v)
$
Substitute the values of areas of the triangles $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$from equation (ii), (iii), (iv) and (v) respectively in equation (i).
$
Ar\left( {ABCDEF} \right) = \dfrac{1}{2}az + \dfrac{1}{2}ay + \dfrac{1}{2}bt + \dfrac{1}{2}cx\\
= \dfrac{1}{2}\left( {az + ay + bt + cx} \right)
$
Therefore, option (B) is the correct answer.
Note: In such types of problems, make sure to find the correct value of base and height for the corresponding triangles to find the total area of the figure. The solution is totally based on the formula of area of the triangle.
Complete step-by-step solution:
The total area of figure $ABCDEF$ is given as the sum of the area of the $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$,that is given as:
$Ar\left( {ABCDEF} \right) = Ar\left( {\Delta ABC} \right) + Ar\left( {\Delta BCD} \right) + Ar\left( {\Delta BED} \right) + Ar\left( {\Delta EFD} \right)$ ……(i)
In triangle $\Delta ABC$,
Base of the triangle is $a$.
Height of the triangle is $z$.
Hence, area of the triangle is given by,
$
\Delta ABC = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times z……(ii)
$
In triangle $\Delta BCD$,
Base of the triangle is $a$.
Height of the triangle is $y$.
Hence, area of the triangle is given by,
$
\Delta BCD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times y……(iii)
$
In triangle $\Delta BED$,
Base of the triangle is$b$ .
Height of the triangle is$t$.
Hence, area of the triangle is given by,
$
\Delta BED = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times b \times t……(iv)
$
In triangle $\Delta EFD$,
Base of the triangle is $c$.
Height of the triangle is $x$.
Hence, area of the triangle is given by,
$
\Delta EFD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times c \times x ……(v)
$
Substitute the values of areas of the triangles $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$from equation (ii), (iii), (iv) and (v) respectively in equation (i).
$
Ar\left( {ABCDEF} \right) = \dfrac{1}{2}az + \dfrac{1}{2}ay + \dfrac{1}{2}bt + \dfrac{1}{2}cx\\
= \dfrac{1}{2}\left( {az + ay + bt + cx} \right)
$
Therefore, option (B) is the correct answer.
Note: In such types of problems, make sure to find the correct value of base and height for the corresponding triangles to find the total area of the figure. The solution is totally based on the formula of area of the triangle.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

