
What is the area of the plot shown in the figure?
A) $\dfrac{1}{2}\left( {az + by + ct + dx} \right)$
B) $\dfrac{1}{2}\left( {bt + cx + ay + az} \right)$
C) $\dfrac{1}{2}\left( {cx + bt + by + az} \right)$
D) $\dfrac{1}{2}\left( {d + t} \right)\left( {c + x} \right) + \dfrac{1}{2}\left( {a + b} \right)\left( {y + z} \right)$

Answer
484.2k+ views
Hint: The given figure consists of four triangles. The formula to find the area of the triangle when its base and height is given is: $\dfrac{1}{2}bh$ where $b$ stands for base and $h$ stands for height.
Complete step-by-step solution:
The total area of figure $ABCDEF$ is given as the sum of the area of the $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$,that is given as:
$Ar\left( {ABCDEF} \right) = Ar\left( {\Delta ABC} \right) + Ar\left( {\Delta BCD} \right) + Ar\left( {\Delta BED} \right) + Ar\left( {\Delta EFD} \right)$ ……(i)
In triangle $\Delta ABC$,
Base of the triangle is $a$.
Height of the triangle is $z$.
Hence, area of the triangle is given by,
$
\Delta ABC = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times z……(ii)
$
In triangle $\Delta BCD$,
Base of the triangle is $a$.
Height of the triangle is $y$.
Hence, area of the triangle is given by,
$
\Delta BCD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times y……(iii)
$
In triangle $\Delta BED$,
Base of the triangle is$b$ .
Height of the triangle is$t$.
Hence, area of the triangle is given by,
$
\Delta BED = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times b \times t……(iv)
$
In triangle $\Delta EFD$,
Base of the triangle is $c$.
Height of the triangle is $x$.
Hence, area of the triangle is given by,
$
\Delta EFD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times c \times x ……(v)
$
Substitute the values of areas of the triangles $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$from equation (ii), (iii), (iv) and (v) respectively in equation (i).
$
Ar\left( {ABCDEF} \right) = \dfrac{1}{2}az + \dfrac{1}{2}ay + \dfrac{1}{2}bt + \dfrac{1}{2}cx\\
= \dfrac{1}{2}\left( {az + ay + bt + cx} \right)
$
Therefore, option (B) is the correct answer.
Note: In such types of problems, make sure to find the correct value of base and height for the corresponding triangles to find the total area of the figure. The solution is totally based on the formula of area of the triangle.
Complete step-by-step solution:
The total area of figure $ABCDEF$ is given as the sum of the area of the $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$,that is given as:
$Ar\left( {ABCDEF} \right) = Ar\left( {\Delta ABC} \right) + Ar\left( {\Delta BCD} \right) + Ar\left( {\Delta BED} \right) + Ar\left( {\Delta EFD} \right)$ ……(i)
In triangle $\Delta ABC$,
Base of the triangle is $a$.
Height of the triangle is $z$.
Hence, area of the triangle is given by,
$
\Delta ABC = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times z……(ii)
$
In triangle $\Delta BCD$,
Base of the triangle is $a$.
Height of the triangle is $y$.
Hence, area of the triangle is given by,
$
\Delta BCD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times a \times y……(iii)
$
In triangle $\Delta BED$,
Base of the triangle is$b$ .
Height of the triangle is$t$.
Hence, area of the triangle is given by,
$
\Delta BED = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times b \times t……(iv)
$
In triangle $\Delta EFD$,
Base of the triangle is $c$.
Height of the triangle is $x$.
Hence, area of the triangle is given by,
$
\Delta EFD = \dfrac{1}{2}bh\\
= \dfrac{1}{2} \times c \times x ……(v)
$
Substitute the values of areas of the triangles $\Delta ABC$,$\Delta BCD$,$\Delta BED$and$\Delta EFD$from equation (ii), (iii), (iv) and (v) respectively in equation (i).
$
Ar\left( {ABCDEF} \right) = \dfrac{1}{2}az + \dfrac{1}{2}ay + \dfrac{1}{2}bt + \dfrac{1}{2}cx\\
= \dfrac{1}{2}\left( {az + ay + bt + cx} \right)
$
Therefore, option (B) is the correct answer.
Note: In such types of problems, make sure to find the correct value of base and height for the corresponding triangles to find the total area of the figure. The solution is totally based on the formula of area of the triangle.
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 10 biology CBSE

Dr BR Ambedkars fathers name was Ramaji Sakpal and class 10 social science CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the full form of POSCO class 10 social science CBSE
