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# What are the bond angles of a molecule with trigonal bipyramidal geometry?

Last updated date: 25th Jul 2024
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Hint: Bond angle of any molecule is defined as the angle between two adjacent carbon atoms. The atoms having trigonal bipyramidal geometry consist of 2 bond angles. These bond angles and the geometry of the molecule are a result of the valence electrons of the bonded atoms distributed as bond and lone pairs.

The axial bonds in the molecule have the angle of $90{}^\circ$ while; the equatorial bonds that are present beside each other have an angle of $120{}^\circ$. This happens as the axial bonds are surrounded by 3 equatorial bonds while the equatorial bonds are surrounded by 2 bonds adjacent to each of them.
Example of trigonal bipyramidal geometry is $PC{{l}_{5}}$and is as follows:
So, the bond angles in the molecule having trigonal bipyramidal geometry are $90{}^\circ$ axial bonds and $120{}^\circ$ equatorial bonds.