Question

An object is placed between F and O of a convex lens. The image formed is:
A. real, inverted and magnified
B. virtual, inverted and magnified
C. virtual, erect and diminished
D. virtual, erect and magnified

Answer 1

Hint: To get the image formed by a lens the way of tracking the rays of light is used. The rays are coming from the object and the image is formed where these rays meet after passing through the lens. If the rays after passing through the lens are diverging, that is are never going to meet, then the diverging rays are drawn so that they seem to be coming from a point and at that point, a virtual image is formed.

Complete step-by-step solution:
The image formation by lenses takes place due to the bending of rays while passing through them. And thus, to get the image formed by a lens the way of tracking the rays of light is used. For convenience purpose, the following rays are traced while trying to get the image formed: -
1. The ray that is going into the lens parallel to the optical axis; this ray gets bent to go through the focal point.
2. The ray that passes through the center; this ray does not bend.
3. The ray that passes through the focal point into the lens; this ray is refracted to be parallel with the optical axis.
We trace these rays coming from the object and the image is formed where these rays meet after passing through the lens. If the rays after passing through the lens are diverging, that is are never going to meet, then the diverging rays are drawn so that they seem to be coming from a point and at that point, a virtual image is formed.
Coming to the question, let us trace the rays
As we can clearly see from the diagram the rays seem to be diverging and the image formed would be virtual, erect, and magnified.
So, Option B is the correct one.

Note: To get the exact position of the image formed lens formula is used. It gives the exact position of the formed image and a similar formula can be used to get the height of the image and the magnification of the lens. The Lens Formula is given as
\[\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\], where v and u are the distance of image and object form the optical center respectively, the distance is taken with proper sign convention.